在 SQL 服务器 2008 中使用分组依据和排序依据检索结果时出错

Question

我有一个名为 Scripts 的 table，其中包含修改后的过程、函数和 tables 的数据。

CREATE TABLE #Scripts
    (
    ID              NUMERIC (18) IDENTITY NOT NULL, 
    [Date]          DATETIME NULL,
    DatabaseName    VARCHAR (50) NULL,
    Name            VARCHAR (100) NULL,
    Type            VARCHAR (20) NULL,
    Action          VARCHAR (50) NULL,
    Description     VARCHAR (500) NULL,
    ModifiedBy      VARCHAR (50) NULL,      
    AddedTimestamp  DATETIME NULL,
    UpdateTimestamp DATETIME NULL,  
    )
GO

然后我将记录添加到 table 中，如下所示。这些只是示例记录。

INSERT INTO #Scripts ([Date], DatabaseName, Name, Type, Action, Description, ModifiedBy, AddedTimestamp, UpdateTimestamp)
VALUES ('2015-01-07 11:16:41.4', 'Test', 'sp_GetData', 'Stored Procedure', 'Created', 'To Get ActivitySubscriptions for Mobile from tblSubscriptions', 'dinesh.alla', '2015-01-07 11:39:39.703', '2015-01-07 11:39:39.703')
GO

INSERT INTO #Scripts ([Date], DatabaseName, Name, Type, Action, Description, ModifiedBy, AddedTimestamp, UpdateTimestamp)
VALUES ('2015-01-07 11:16:41.4', 'Test', 'sp_GetData', 'Stored Procedure', 'Updated', 'To Get ActivitySubscriptions for Mobile from tblSubscriptions', 'dinesh.alla', '2015-01-07 11:39:39.703', '2015-01-07 11:39:39.703')
GO


INSERT INTO #Scripts ([Date], DatabaseName, Name, Type, Action, Description, ModifiedBy, AddedTimestamp, UpdateTimestamp)
VALUES ('2015-01-07 11:16:41.4', 'Test', 'sp_GetData', 'Stored Procedure', 'Deleted', 'To Get ActivitySubscriptions for Mobile from tblSubscriptions', 'dinesh.alla', '2015-01-07 11:39:39.703', '2015-01-07 11:39:39.703')
GO

INSERT INTO #Scripts ([Date], DatabaseName, Name, Type, Action, Description, ModifiedBy, AddedTimestamp, UpdateTimestamp)
VALUES ('2015-01-07 11:16:41.4', 'Test', 'sp_UpdateData', 'Stored Procedure', 'Created', 'To Get ActivitySubscriptions for Mobile from tblSubscriptions', 'dinesh.alla', '2015-01-07 11:39:39.703', '2015-01-07 11:39:39.703')
GO

INSERT INTO #Scripts ([Date], DatabaseName, Name, Type, Action, Description, ModifiedBy, AddedTimestamp, UpdateTimestamp)
VALUES ('2015-01-07 11:16:41.4', 'Test', 'sp_UpdateData', 'Stored Procedure', 'Updated', 'To Get ActivitySubscriptions for Mobile from tblSubscriptions', 'dinesh.alla', '2015-01-07 11:39:39.703', '2015-01-07 11:39:39.703')
GO

INSERT INTO #Scripts ([Date], DatabaseName, Name, Type, Action, Description, ModifiedBy, AddedTimestamp, UpdateTimestamp)
VALUES ('2015-01-07 11:16:41.4', 'Test', 'sp_AddData', 'Stored Procedure', 'Created', 'To Get ActivitySubscriptions for Mobile from tblSubscriptions', 'dinesh.alla', '2015-01-07 11:39:39.703', '2015-01-07 11:39:39.703')
GO

我尝试得到如下所示的结果

SELECT MAX(ID) AS ID,MAX(Action) AS Action 
FROM #Scripts GROUP BY Name ORDER BY ID ASC

输出：

ID     Action
3      Updated
5      Updated
6      Created

预期输出：

ID     Action
3      Deleted
5      Updated
6      Created

Answer 1

试试这个：

 select distinct sc.action,sc.ID from (
  SELECT MAX(ID)  OVER(PARTITION BY NAME  ) rn,*  FROM #Scripts  
  )d  join #Scripts sc
  on d.rn=sc.ID
 order by sc.ID

输出

action  ID
Deleted 3
Updated 5
Created 6

Answer 2

假设您将其中两个操作设置为 'a' 和 'z' .. 那么 select max(Actions) 的结果将是 z

如果你想要预期的输出那么你可以尝试这样的事情

select TOP 1 MAX(ID) AS ID ,Action
FROM #Scripts where Name = 'sp_GetData'
GROUP BY Action
ORDER BY MAX(ID) DESC

请仔细阅读 this link 你会明白的

Answer 3

;WITH LatestChanges AS
(
    SELECT  S.[ID], S.[Date], S.[DatabaseName], S.[Name], S.[Type], S.[Action], S.[Description],
            S.[ModifiedBy], S.[AddedTimestamp], S.[UpdateTimestamp],
            [RowNum] = ROW_NUMBER() OVER (PARTITION BY S.[Name] ORDER BY S.[ID] DESC)
    FROM    [#Scripts] S
)
SELECT  *
FROM    LatestChanges
WHERE   [RowNum] = 1
ORDER BY ID

每个 [Name] 的 returns 最后一个 [ID]。

Answer 4

试试这个，

SELECT * FROM 
(
   SELECT *,
   ROW_NUMBER() OVER(PARTITION BY NAME ORDER BY ID DESC )RN
   FROM @Scripts 
)T4
WHERE RN=1

在 SQL 服务器 2008 中使用分组依据和排序依据检索结果时出错

Got Error in Retrieving results using group by and order by in SQL server 2008

sql

sql-server

database

sql-server-2008

select