Python Denary 到二进制转换器

Question

嗨，你能帮我把十进制值转换成二进制和十六进制吗？我必须输入一个介于 0 和 15 之间的数字，输出应该是它的十六进制和二进制等效值。这是我到目前为止所做的：

    denary_list=           ["0","1","2","3","4","5","6","7","8","9","10","11","12","13","14","15"]
    print("denary list")


binary_list=["0000","0001","0010","0011","0100","0101","0110","0111","1000","1001","1010","1011","1100","1101","1110","1111"]
print("binary list")

hex_list=["0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"]
print("hex list")
option=input("enter choice:\n1.print values\n2.convert denary number to binary and hex\n3. Convert a hex value between 0 and 15 to denary or binary value\n9. Quit")
if option=='1':
   print ("denary","\t","binary","hex")
   count1=0
   while count1<len(denarylist) and count1<len(binarylist) and count1<len(hexlist):
       print(denarylist[count1],"\t",binarylist[count1],"\t",hexlist[count1])
       count1+=1
if option=='2':
  number=int(input("what number do you choose to convert to binary and hex"))
  if number<=15 and number>=0:

Answer 1

使用 format 方法代替 b 和 x 格式代码将整数格式化为十六进制或二进制数：

>>> format(1234, 'b')
'10011010010'
>>> format(1234, 'x')
'4d2'

使用int('01234fff', 16)将十六进制字符串转换为数字；同样 int('11110000', 2) 将二进制字符串转换为数字。

并回答您原来的问题：您可以使用 binary_list[number] 获得第号个项目（从零开始的索引），因此您可以将选项 2 写为

number = int(input("what number do you choose to convert to binary and hex"))
if 0 <= number <= 15:
    print("the number in binary is", binary_list[number])
    print("the number in hex is", hex_list[number])

Answer 2

这是我自己的二进制到二进制转换器的版本：

Number = int(input("Enter a number to convert: ")) 

if Number < 0:
    print ("Can't be less than 0")
else:
    Remainder = 0
    String = ""
    while Number > 0:
        Remainder = Number % 2
        Number = Number //2
        String = str(Remainder) + String
    print (String)

Python Denary 到二进制转换器

Python Denary to Binary Convertor

python

binary