如何按组获取累计和

Question

这是想要的结果：

在 ID=14 时，我需要用新 cum_value 重新设置附加值。

SQL : (fiddle : http://sqlfiddle.com/#!6/62f01/14)

Answer 1

到目前为止你还没有，但我已经尝试了不那么复杂的查询：

DECLARE @t table(
        id int
        )

INSERT  INTO @t (id)
VALUES  (0),(1),(2),(3),(4),(5),(6),
        (7),(8),(9),(10),(11),(12),(13),
        (14),(15),(16),(17),(18),(19),
        (20),(21),(22),(23),(24),(99);

SELECT  *
        ,SUM(id)
         OVER(ORDER BY id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Cum_STEPID
FROM    @t
WHERE   id < 14
UNION
SELECT  *
        ,SUM(CASE WHEN id = 14 THEN 91000 ELSE id END)
         OVER(ORDER BY id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) AS Cum_STEPID
FROM    @t
WHERE   id >= 14

如何按组获取累计和

How to get cumulative sum by group

sql

sql-server-2012

sum

partition