Random.Range 不能使用整数，为什么？

Question

所以我正在做这个开锁项目，它真的很简单，但我遇到了一些问题 Random.Range 当我按下按键时它不会改变我设置了。我的场景非常简单，我有一扇门，里面有脚本，还有 Unity 的第一人称控制器。我希望 Random.Range 在我按下 1 到 9 键时更改值然后打印两者，如果它们等于或大于 collider.isTrigger 设置为 true。

#pragma strict

public var playerrangel : int = 0;
public var  lockStrength : int = 1;

function Update () 
{  
    if (playerrangel == lockStrength || playerrangel >lockStrength){    
    // if both Ranges of player and lock are  equal or greater then it sets Door Trigger to true.

    collider.isTrigger = true;
    print ("Door unlocked!");

}
else  {                                                 
    // if both Ranges of player and lock aren't  equal or greater then it sets Door Trigger to false.

   collider.isTrigger = false;

}

// The player enters range of the lock  - 1 to 9.

if (Input.GetKeyDown ("1")) {       
    // Select Range 1

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");
}
if (Input.GetKeyDown ("2")) {    
    // Select Range 2

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");

}
if (Input.GetKeyDown ("3")) {     
    // Select Range 3

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");


}
if (Input.GetKeyDown ("4")) {    
    // Select Range 4

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");

}
if (Input.GetKeyDown ("5")) {   
    // Select Range 5

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");


}
if (Input.GetKeyDown ("6")) {   
    // Select Range 6

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");

}
if (Input.GetKeyDown ("7")) {   
    // Select Range 7

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");

}
if (Input.GetKeyDown ("8")) {   
    // Select Range 8

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");

}
if (Input.GetKeyDown ("9")) {   
    // Select Range 9

    print (playerrangel + " Player Range");
    print (lockStrength  + " Lock Strength");

}
}

function OnTriggerEnter () {

    playerrangel = Random.Range(1,30);
    lockStrength = Random.Range(1,40);

}

我还有一个问题，当门被解锁时我能做些什么 Input.GetKeyDown 关闭所以玩家不能将它改回 false 并且只打印一次 "Door Unlocked!".

Answer 1

当你想改变它时，你应该再次调用Random.Range函数。 OnTriggerEnter 只会在碰撞开始时被调用。我建议改为这样：

int range = 0;
if (Input.GetKeyDown ("5")) {   // Select Range 5
    range = 5;
else if (Input.GetKeyDown ("6")) {   // Select Range 6
    range = 6;

if (range != 0)
{
    int playerrangel = Random.Range(1,30);
    int lockStrength = Random.Range(1,40);
    // now do something with these values
}

对于你的另一个问题，你不能关闭Input.GetKeyDown，但你可以跳过检查发生的功能：if (!doorOpened) CheckInput();。那么很明显，你在播放成功后设置doorOpened=true;

Random.Range 不能使用整数，为什么？

Random.Range not working with integer, why?

unity3d

unityscript

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