没有 procedure/function/signature
No procedure/function/signature
我在使用存储过程方面比较陌生,而且我确实 运行 碰壁了。我在使用 Spring JdbcTemplate 时收到以下错误消息。我的开发环境是 Xubuntu,jdk 1.8.
堆栈跟踪是:
Exception in thread "main" org.springframework.dao.InvalidDataAccessApiUsageException: Unable to determine the correct call signature - no procedure/function/signature for 'PROCONEINPARAMETER'
at org.springframework.jdbc.core.metadata.GenericCallMetaDataProvider.processProcedureColumns(GenericCallMetaDataProvider.java:347)
at org.springframework.jdbc.core.metadata.GenericCallMetaDataProvider.initializeWithProcedureColumnMetaData(GenericCallMetaDataProvider.java:112)
at org.springframework.jdbc.core.metadata.CallMetaDataProviderFactory.processMetaData(CallMetaDataProviderFactory.java:133)
at org.springframework.jdbc.support.JdbcUtils.extractDatabaseMetaData(JdbcUtils.java:299)
at org.springframework.jdbc.core.metadata.CallMetaDataProviderFactory.createMetaDataProvider(CallMetaDataProviderFactory.java:73)
at org.springframework.jdbc.core.metadata.CallMetaDataContext.initializeMetaData(CallMetaDataContext.java:286)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.compileInternal(AbstractJdbcCall.java:303)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.compile(AbstractJdbcCall.java:288)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.checkCompiled(AbstractJdbcCall.java:348)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.doExecute(AbstractJdbcCall.java:375)
at org.springframework.jdbc.core.simple.SimpleJdbcCall.executeFunction(SimpleJdbcCall.java:153)
at test.jdbc.StringDao.executeProcOneINParameter(StringDao.java:21)
at test.jdbc.SimpleJdbcTest.main(SimpleJdbcTest.java:15)
代码:
SimpleJdbc.java
package test.jdbc;
import java.util.Map;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class SimpleJdbcTest {
public static void main(String[] args) {
ApplicationContext ctx=new ClassPathXmlApplicationContext("applicationContext.xml");
StringDao dao=(StringDao)ctx.getBean("edao");
String request = new String(" Wow, this works!");
String response = dao.executeProcOneINParameter(request);
if (response != null && !response.equals(new String())) {
System.out.println("stored proc worked: "+ response);
} else {
System.err.println("stored proc did not work.");
}
}
}
StringDao.java
package test.jdbc;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.simple.SimpleJdbcCall;
public class StringDao {
private static final String PROC_NAME = "PROCONEINPARAMETER";
private static final String CAT_NAME = "LISTENER";
private JdbcTemplate jdbcTemplate;
public void setJdbcTemplate(JdbcTemplate jdbcTemplate) {
this.jdbcTemplate = jdbcTemplate;
}
public String executeProcOneINParameter(String callParam){
SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
.withCatalogName(CAT_NAME)
.withProcedureName(PROC_NAME);
return jdbcCall.executeFunction(String.class, callParam);
}
}
存储过程:
PROCONEINPARAMETER
CREATE OR REPLACE PROCEDURE procOneINParameter(param1 IN VARCHAR2)
IS
BEGIN
DBMS_OUTPUT.PUT_LINE('Hello World IN parameter ' || param1);
END;
您正在尝试调用过程,而不是函数。但是您通过 executeFunction()
方法调用它,并指定 return 类型的 String
.
您需要改用 execute()
,仍然传递过程参数,但没有 return 类型(因为没有来自过程的类型):
Map<String,Object> out = jdbcCall.execute(callParam);
您的程序也没有任何 OUT 参数,因此 out
将为空。
除了@Alex 发布的问题和我更正的问题外,最后的问题如下:
static final String PROC_NAME = "PROCONEINPARAMETER";
private static final String CAT_NAME = "LISTENER";
…..
SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
.withCatalogName(CAT_NAME)
.withProcedureName(PROC_NAME);
而不是:
SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
.withSchemaName(CAT_NAME)
.withProcedureName(PROC_NAME);
显然,没有人知道我在交替使用目录和架构名称。
我在使用存储过程方面比较陌生,而且我确实 运行 碰壁了。我在使用 Spring JdbcTemplate 时收到以下错误消息。我的开发环境是 Xubuntu,jdk 1.8.
堆栈跟踪是:
Exception in thread "main" org.springframework.dao.InvalidDataAccessApiUsageException: Unable to determine the correct call signature - no procedure/function/signature for 'PROCONEINPARAMETER'
at org.springframework.jdbc.core.metadata.GenericCallMetaDataProvider.processProcedureColumns(GenericCallMetaDataProvider.java:347)
at org.springframework.jdbc.core.metadata.GenericCallMetaDataProvider.initializeWithProcedureColumnMetaData(GenericCallMetaDataProvider.java:112)
at org.springframework.jdbc.core.metadata.CallMetaDataProviderFactory.processMetaData(CallMetaDataProviderFactory.java:133)
at org.springframework.jdbc.support.JdbcUtils.extractDatabaseMetaData(JdbcUtils.java:299)
at org.springframework.jdbc.core.metadata.CallMetaDataProviderFactory.createMetaDataProvider(CallMetaDataProviderFactory.java:73)
at org.springframework.jdbc.core.metadata.CallMetaDataContext.initializeMetaData(CallMetaDataContext.java:286)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.compileInternal(AbstractJdbcCall.java:303)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.compile(AbstractJdbcCall.java:288)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.checkCompiled(AbstractJdbcCall.java:348)
at org.springframework.jdbc.core.simple.AbstractJdbcCall.doExecute(AbstractJdbcCall.java:375)
at org.springframework.jdbc.core.simple.SimpleJdbcCall.executeFunction(SimpleJdbcCall.java:153)
at test.jdbc.StringDao.executeProcOneINParameter(StringDao.java:21)
at test.jdbc.SimpleJdbcTest.main(SimpleJdbcTest.java:15)
代码:
SimpleJdbc.java
package test.jdbc;
import java.util.Map;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class SimpleJdbcTest {
public static void main(String[] args) {
ApplicationContext ctx=new ClassPathXmlApplicationContext("applicationContext.xml");
StringDao dao=(StringDao)ctx.getBean("edao");
String request = new String(" Wow, this works!");
String response = dao.executeProcOneINParameter(request);
if (response != null && !response.equals(new String())) {
System.out.println("stored proc worked: "+ response);
} else {
System.err.println("stored proc did not work.");
}
}
}
StringDao.java
package test.jdbc;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.simple.SimpleJdbcCall;
public class StringDao {
private static final String PROC_NAME = "PROCONEINPARAMETER";
private static final String CAT_NAME = "LISTENER";
private JdbcTemplate jdbcTemplate;
public void setJdbcTemplate(JdbcTemplate jdbcTemplate) {
this.jdbcTemplate = jdbcTemplate;
}
public String executeProcOneINParameter(String callParam){
SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
.withCatalogName(CAT_NAME)
.withProcedureName(PROC_NAME);
return jdbcCall.executeFunction(String.class, callParam);
}
}
存储过程:
PROCONEINPARAMETER
CREATE OR REPLACE PROCEDURE procOneINParameter(param1 IN VARCHAR2)
IS
BEGIN
DBMS_OUTPUT.PUT_LINE('Hello World IN parameter ' || param1);
END;
您正在尝试调用过程,而不是函数。但是您通过 executeFunction()
方法调用它,并指定 return 类型的 String
.
您需要改用 execute()
,仍然传递过程参数,但没有 return 类型(因为没有来自过程的类型):
Map<String,Object> out = jdbcCall.execute(callParam);
您的程序也没有任何 OUT 参数,因此 out
将为空。
除了@Alex 发布的问题和我更正的问题外,最后的问题如下:
static final String PROC_NAME = "PROCONEINPARAMETER";
private static final String CAT_NAME = "LISTENER";
…..
SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
.withCatalogName(CAT_NAME)
.withProcedureName(PROC_NAME);
而不是:
SimpleJdbcCall jdbcCall = new SimpleJdbcCall(jdbcTemplate)
.withSchemaName(CAT_NAME)
.withProcedureName(PROC_NAME);
显然,没有人知道我在交替使用目录和架构名称。