需要更正或建议 javascript 来计算两个日期之间的差异

Question

年龄计算

我从许多网站上收集了这个JavaScript；我想获得两个不同日期之间的年龄；
在这个脚本或示例中，我希望向我的女儿展示 age;;一切顺利 直到她的年龄超过 6 个月,

该脚本将年龄四舍五入到上面的数字，即 （在这种情况下为一年） 和 向下舍入显示月份数字的月份。

好吧，如果 少于 365 天 ，我希望脚本查看四舍五入到较小数字的年份， 以及自少于 365 天.

后的月份 四舍五入

<!-- Calculate Age -->
<script type="text/javascript">
var s = '2016-01-31T17:17:28.593Z';
var a = s.split(/[^0-9]/);
var d=new Date (a[0],a[1]-1,a[2],a[3],a[4],a[5] );
var fromDate = new Date(d);
var toDate = new Date();

// current date format as mm-dd-yyyy 
    var Start_Date = new Date(d);
    var sec = Start_Date.getSeconds();
    var min = Start_Date.getMinutes();
    var hr = Start_Date.getHours();
    var dd = Start_Date.getDate();
    var mm = Start_Date.getMonth()+1; //January is 0!
    var yyyy = Start_Date.getFullYear();
 if(dd<10){
   dd='0'+dd
  } 
 if(mm<10){
   mm='0'+mm
  }
 if(hr<10){
   hr='0'+hr
  }
 if(min<10){
   min='0'+min
  }
var Start_Date = dd+'-'+mm+'-'+yyyy+'&nbsp at <span style="direction:ltr; color:red ;font-weight:700;">[&nbsp'+hr+ ":" +min+ ":" +sec+'&nbsp]</span>';
// End date format as mm-dd-yyyy
// Start_Date = str;
var differenceTravel = toDate.getTime() - fromDate.getTime();
// var months = Math.ceil (toDate.getMonth() - fromDate.getMonth() + (12 * (toDate.getFullYear() - 
// 1 day = 86400000,
var Tyears = Math.round(differenceTravel/1000/60/60/24/365);
var Tmonths = Math.round((differenceTravel - (Tyears * 365*60*60*24*1000)) / (1000*60*60*24*30));
var Tdays = Math.round((differenceTravel - (Tyears *60*60*24*365*1000) - (Tmonths *60*60*24*30*1000))/ (86400000));
//
document.writeln('<div style="color:Blue">');
document.writeln('<ul>');
document.writeln('<li><span style="color:Navy">Seba Birthday:&nbsp;</span> ' + Start_Date +'</li>');
document.write('<li><span style="color:MediumVioletRed">Her age is:</span>&nbsp; '+ Tyears +'<span style="color:Green">&nbsp;year &nbsp; and &nbsp; </span>'+ Tmonths +'<span style="color:Green">&nbsp;months &nbsp; and &nbsp;</span>'+ Tdays +'<span style="color:Green">&nbsp;days</span></li>');
document.writeln('</ul></div>');
</script>
<!-- / good -->

Answer 1

如果要向下舍入，请使用 Math.floor，而不是 Math.round，这将根据值是 < 还是 > 而向上或向下舍入0.5.

Answer 2

更改这三行：

var Tyears = Math.round(differenceTravel/1000/60/60/24/365);
var Tmonths = Math.round((differenceTravel - (Tyears * 365*60*60*24*1000)) / (1000*60*60*24*30));
var Tdays = Math.round((differenceTravel - (Tyears *60*60*24*365*1000) - (Tmonths *60*60*24*30*1000))/ (86400000));

以下内容：

var Tyears = Math.floor(differenceTravel/1000/60/60/24/365);
var Tmonths = Math.ceil((differenceTravel - (Tyears * 365*60*60*24*1000)) / (1000*60*60*24*30));
var Tdays = Math.round((differenceTravel - (Tyears *60*60*24*365*1000) - (Tmonths *60*60*24*30*1000))/ (86400000));