Segmentation fault 错误来了

Question

#include<stdio.h> 
#include<conio.h>
#include<stdlib.h>

void main() 
{   
  int n;
  void towers(int n,char from, char to,char aux); 
  clrscr();
  printf("\n\t\t PROGRAM FOR TOWERS OF HANOI"); 
  printf("\n\nEnter The Total number of Disks : "); 
  scanf("%d",n);    towers(n,'A','C','B'); 

  getch();
} 
void towers(int n,char from,char to, char aux)
{ 
  if(n==1)
  {     
        printf("\nMove disk 1 from %c peg to %c peg",from,to);  
        return; 
  } 
  towers(n-1,from,aux,to); 
  printf("\n Move disk %d from %c peg to %c peg",n,from,to); 
  towers(n-1,aux,to,from);
}

Answer 1

将 scanf("%d",n) 替换为 scanf("%d",&n)，传递指向 scanf 应放置结果的位置的指针。

Answer 2

使用

scanf("%d",&n);

而不是

scanf("%d",n);

因为它需要变量n的地址给scanf函数来存值。因此，该地址是通过 & n.

指定的

Segmentation fault 错误来了

Segmentation fault Error comes

c

turbo-c++