如何使用单个查询通过 PHP 创建多个 MySQL 表？

Question

我正在尝试为我的网站创建 "setup script"。我想创建数据库，同时添加表和一些内容。到目前为止，这就是我的做法，但使用多个查询似乎有些混乱：

<?php


$servername = "localhost";
$username = "root";
$password = "password";

// Create connection
$conn = new mysqli($servername, $username, $password);
// Check connection
if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
}

// Create database
$sql = "CREATE DATABASE MYDB";
if ($conn->query($sql) === TRUE) {

    echo "1. Database created successfully <br/>";
    $conn->select_db("MYDB");


    $sql_members = "CREATE TABLE MEMBERS (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    USERNAME VARCHAR(30) NOT NULL,
    EMAIL VARCHAR(40) NOT NULL,
    DISCOUNT VARCHAR(5),
    PASSW CHAR(128),
    ROLE VARCHAR(9)
    )";


    if ($conn->query($sql_members) === TRUE) {
        echo "2. Table MEMBERS created successfully <br/>";
    } else {
        echo "Error creating table: " . $conn->error;
    }

    $sql_content = "CREATE TABLE CONTENT (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    TITLE VARCHAR(30) NOT NULL,
    TEXT VARCHAR(30) NOT NULL
    )";

    if ($conn->query($sql_content) === TRUE) {
        echo "3. Table CONTENT created successfully <br/>";
    } else {
        echo "Error creating table: " . $conn->error;
    }



} else {
    echo "Error creating database: " . $conn->error;
}

$conn->close();


?>

有没有更好的方法？谢谢！

==更新==

我尝试导出数据库并使用生成的 .sql 文件作为我的设置查询，但出了点问题，我得到：

Error creating tables: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'INSERT INTO CONTACTS (ID, NAME, PHONE, EMAIL, ADDRESS, CITY, `COUN' at line 12

CREATE TABLE IF NOT EXISTS `CONTACTS` (
  `ID` int(11) NOT NULL AUTO_INCREMENT,
  `NAME` varchar(25) COLLATE utf8_romanian_ci NOT NULL,
  `PHONE` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
  `EMAIL` varchar(35) COLLATE utf8_romanian_ci NOT NULL,
  `ADDRESS` text COLLATE utf8_romanian_ci NOT NULL,
  `CITY` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
  `COUNTRY` varchar(16) COLLATE utf8_romanian_ci NOT NULL,
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 COLLATE=utf8_romanian_ci AUTO_INCREMENT=2 ;

INSERT INTO `CONTACTS` (`ID`, `NAME`, `PHONE`, `EMAIL`, `ADDRESS`, `CITY`, `COUNTRY`) VALUES
(1, 'Peter Brown', '0742062307', 'office@shop.com', 'Avenue 13.', 'Santaclaus', 'Austria');

== 解决方案 ==

我需要 "multi_query()" 来执行我的多个查询。

Answer 1

你可以export the whole database including all tables using the command line or using PhPMyAdmin。然后查询php中的文件内容，创建数据库

Answer 2

您可以创建一个文件并将所有 sql 查询放入其中..

CREATE TABLE MEMBERS (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    USERNAME VARCHAR(30) NOT NULL,
    EMAIL VARCHAR(40) NOT NULL,
    DISCOUNT VARCHAR(5),
    PASSW CHAR(128),
    ROLE VARCHAR(9)
);

CREATE TABLE CONTENT (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    TITLE VARCHAR(30) NOT NULL,
    TEXT VARCHAR(30) NOT NULL
);

然后在您的 php 代码中：

$query = file_get_contents ('queries.sql');

if ($conn->query($query) === TRUE) {
    echo "all tables created successfully <br/>";
} else {
    echo "Error creating tables: " . $conn->error;
}

Answer 3

你也可以试试这个:p

$errors = [];

$table1 = "CREATE TABLE MEMBERS (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    USERNAME VARCHAR(30) NOT NULL,
    EMAIL VARCHAR(40) NOT NULL,
    DISCOUNT VARCHAR(5),
    PASSW CHAR(128),
    ROLE VARCHAR(9)
    )";

$table2 = "CREATE TABLE CONTENT (
    id INT(6) UNSIGNED AUTO_INCREMENT PRIMARY KEY,
    TITLE VARCHAR(30) NOT NULL,
    TEXT VARCHAR(30) NOT NULL
    )";


$tables = [$table1, $table2];


foreach($tables as $k => $sql){
    $query = @$conn->query($sql);

    if(!$query)
       $errors[] = "Table $k : Creation failed ($conn->error)";
    else
       $errors[] = "Table $k : Creation done";
}


foreach($errors as $msg) {
   echo "$msg <br>";
}

如何使用单个查询通过 PHP 创建多个 MySQL 表？

How to create multiple MySQL tables via PHP using a single query?

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