为什么 ulimit -t 不杀死超过 time.sleep 限制的进程？

Question

我正在尝试使用 ulimit -t 限制一个 python 脚本的 CPU 使用。脚本包含一条time.sleep()语句，在指定的时间限制后不被杀死。这是名为 test.py:

的简化 python 脚本

import time

while True:
    time.sleep(0.1)

我运行命令如下：

ulimit -v 400000; ulimit -t 30; python test.py

脚本永远保持运行ning。对此有什么解释吗？谢谢。

mata的回答是正确的。我更新了我的真实代码，其中包含一个隐藏的东西，ulimit -t 不计算生成子进程的运行ning 时间。

#!/usr/bin/env python
# Run: python smt.py filename.smt2 timeout
# timeout is in seconds

import os
import subprocess
import sys
import stat
import time

current_path = os.path.dirname(os.path.realpath(__file__))

def remove_tmp (filename, version):
  try:
    os.remove(filename + '.' + version + '.tmp')
  except OSError:
    pass

  try:
    os.remove(os.path.splitext(filename)[0] + '.' + version +  '.out')
  except OSError:
    pass

  try:
    os.remove(os.path.splitext(filename)[0] + '.' + version +  '.in')
  except OSError:
    pass

def run_raSAT (filename, bounds, sbox, timeout):
  startTime = time.time()  

  raSATResult = "unknown"

  # remove tmps files:
  remove_tmp(filename, "0.2")
  remove_tmp(filename, "0.3")

  proc2 = subprocess.Popen([os.path.join(current_path, "./raSAT-0.2"), filename, bounds, 'sbox=' + str(sbox), 'tout=' + str(timeout-(time.time() - startTime))])
  proc3 = subprocess.Popen([os.path.join(current_path, "./raSAT-0.3"), filename, bounds])
  while True:
    if proc2.poll():
      # try read output of 0.2
      try:
        with open(filename + '.0.2.tmp', 'r') as outfile:
          raSATResult = outfile.read().rstrip()
          outfile.close()
          if raSATResult == "unknown":
            sbox /= 10
            remove_tmp(filename, "0.2")
            proc2 = subprocess.Popen([os.path.join(current_path, "./raSAT-0.2"), filename, bounds, 'sbox=' + str(sbox), 'tout=' + str(timeout-(time.time() - startTime))])
      except IOError:
        pass  

    if proc3.poll():      
      # try read output of 0.3
      try:
        with open(filename + '.0.3.tmp', 'r') as outfile:
          raSATResult = outfile.read().rstrip()
          outfile.close()
      except IOError:
        pass

    if raSATResult == "sat" or raSATResult == "unsat":
      if not proc3.poll():
        proc3.kill()
      if not proc2.poll():
        proc2.kill()
      break

    time.sleep(0.01)


  return raSATResult, sbox

def run(filename, initLowerBound, initUpperBound, sbox, timeout):
  lowerBound = initLowerBound
  upperBound = initUpperBound
  raSATResult = "unknown"
  startTime = time.time()
  while (raSATResult == 'unknown'):
    (raSATResult, sbox) = run_raSAT(filename, 'lb=' + str(lowerBound) + ' ' + str(upperBound), sbox, timeout - (time.time() - startTime))
    if raSATResult == 'unsat':
      (raSATResult, sbox) = run_raSAT(filename, 'lb=-inf inf', sbox, timeout - (time.time() - startTime))  
  print (raSATResult)

  # remove tmps files:
  remove_tmp(filename, "0.2")
  remove_tmp(filename, "0.3")

# get timeout from environment
timeout = float(os.environ.get('STAREXEC_CPU_LIMIT'))

run(sys.argv[1], -10, 10,  0.1, timeout)

Answer 1

ulimit -t 设置 CPU 时间限制。当您的程序处于休眠状态时，它不会使用任何 CPU 时间，因此该时间不算数。它只会占用几个 CPU 周期再次进入休眠状态，这就是它没有被杀死的原因。

您不能使用 ulimit 指定实时限制。

为什么 ulimit -t 不杀死超过 time.sleep 限制的进程？

Why doesn't ulimit -t kill a process sleeping beyond the limit with time.sleep?

python

ulimit