得到搜索结果后打开另一个activity

Question

我在我的应用程序中使用搜索视图。在获取不同活动的搜索结果后，我遇到了问题。这是 class 显示填充了项目的列表视图。如果用户决定不搜索项目，他们只需单击一个项目即可将他们带到另一个项目 activity。

public class ShowCourses extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_show_courses);

    Toolbar courseToolbar = (Toolbar) findViewById(R.id.courses_toolbar); 
    setSupportActionBar(courseToolbar);
    getSupportActionBar().setTitle(R.string.courses_toolbar);


    String[] subjects = {"Art", "Math", Science"};

    ListAdapter subjectsAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, subjects);
    ListView DisplaySubjects = (ListView) findViewById(R.id.DisplaySubjects);
    DisplaySubjects.setAdapter(subjectsAdapter);


    DisplaySubjects.setOnItemClickListener(
            new AdapterView.OnItemClickListener(){
                @Override
                public void onItemClick(AdapterView<?> parent, View view, int position, long id){
                    switch(position){
                        case 0:
                            Intent art = new Intent(ShowCourses.this, art.class);
                            startActivity(art);
                            break;
                        case 1:
                            Intent math = new Intent(ShowCourses.this, math.class);
                            startActivity(math);
                            break;
                        case 2:
                            Intent science = new Intent(ShowCourses.this, science.class);
                            startActivity(science);
                            break;
                        default:

                            break;
                    }
                }
            });
}

@Override
protected void onResume(){
    super.onResume();
}

@Override
public boolean onCreateOptionsMenu(Menu menu){
    getMenuInflater().inflate(R.menu.menu_main, menu);

    SearchView searchView = (SearchView) menu.findItem(R.id.menu_search).getActionView();
    SearchManager searchManager = (SearchManager) getSystemService(SEARCH_SERVICE);
    searchView.setSearchableInfo(searchManager.getSearchableInfo(getComponentName()));

    return super.onCreateOptionsMenu(menu);
}

}

这是显示搜索结果的activity。如果用户决定搜索让我们说 "math" 那么它会显示一个列表视图只显示数学。

public class CoursesSearchResults extends AppCompatActivity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_courses_search_results);

    Toolbar courseToolbar = (Toolbar) findViewById(R.id.searchCourses_toolbar); //Creates Toolbar
    setSupportActionBar(courseToolbar);

    String query = new String();
    final Intent searchIntent = getIntent();
    if(Intent.ACTION_SEARCH.equals(searchIntent.getAction())){
        query = searchIntent.getStringExtra(SearchManager.QUERY);
        getSupportActionBar().setTitle(query);
        Toast.makeText(CoursesSearchResults.this, query, Toast.LENGTH_SHORT).show();
    }

String[] subjects = {"Art", "Math", Science"};

    final ArrayList<String> searchResults = new ArrayList<String>();
    for(int i = 0; i < subjects.length; i++) {
        if (subjects[i].toLowerCase().contains(query.toLowerCase())) {
            searchResults.add(subjects[i]);
        }
    }


    ListView courses = (ListView) findViewById(R.id.courses_search);
    ListAdapter coursesAdapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, searchResults);
   courses.setAdapter(coursesAdapter);

    courses.setOnItemClickListener(
            new AdapterView.OnItemClickListener(){
                @Override
                public void onItemClick(AdapterView<?> parent, View view, int position, long id){
                      switch(position){
                        case 0:
                            Intent art = new Intent(ShowCourses.this, art.class);
                            startActivity(art);
                            break;
                        case 1:
                            Intent math = new Intent(ShowCourses.this, math.class);
                            startActivity(math);
                            break;
                        case 2:
                            Intent science = new Intent(ShowCourses.this, science.class);
                            startActivity(science);
                            break;
                        default:

                            break;

                }
            });
}
}

我遇到的问题是因为我在单击项目时使用 switch 语句，这取决于位置。因此，如果我搜索 "math"，它将位于零位置，如果我单击它，它会将我带到艺术 activity。它需要通向数学 activity 而不是艺术 activity。如果我搜索科学，它将处于零位置。然后，如果我单击科学，它将引导我进入艺术 activity 而不是科学 activity。如何从搜索结果转到不同的活动？

Answer 1

每次搜索像数学这样的关键字时，它都会排在第 0 位，对吧。你有一个开关条件，检查位置是否为零，然后将 Intent 传递给 Art.class

 switch(position){
                    case 0:
                        Intent art = new Intent(ShowCourses.this,art.class);
                        startActivity(art);
                        break;

现在，不管你搜索什么，如果它在位置 0 让它成为你列表视图中的任何项目，点击将重定向到艺术 Activity。

所以，对于这个问题，我们可以做的是先检查元素的类型，然后在 that.For 示例的基础上重定向到其他页面:-

 courses.setOnItemClickListener(
        new AdapterView.OnItemClickListener(){
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id){
                  String sub = parent.getItemAtPosition(int position).toString();
                  if(sub.equals(subjects[0])){
                        Intent art = new Intent(ShowCourses.this, art.class);
                        startActivity(art);
                        }else if(sub.equals(subjects[1])){
                        Intent math = new Intent(ShowCourses.this, math.class);
                        startActivity(math);
                        }else if(sub.equals(subjects[2])){
                        Intent science = new Intent(ShowCourses.this, science.class);
                        startActivity(science);
                        }

        });

得到搜索结果后打开另一个activity

Opening another activity after getting search results

android

listview

searchview