JQuery table 按包含值的倍数搜索行数

Question

我想在 table 中按 td 的多个 :contains() 值搜索行数。

<table id="tabCity">
<tr><td>Name</td><td>Surname</td><td>City</td></tr>
<tr><td>Paul</td><td color>Smith</td><td>Boston</td></tr>
<tr><td>Andrew</td><td>Smith</td><td>London</td></tr>
<tr><td>Smith</td><td>Green</td><td>Boston</td></tr>
<tr><td>Nick</td><td>Smith</td><td>Boston</td></tr>
</table>
<br>
<button class="go">Search Surname Smith in Boston</button>
<br>
<label>The result must be 2</label>

$(document).on('click', '.go', function(){
var rows= $("#tabCity tr td:nth-child(2):contains('Smith'), td:nth-child(3):contains('Boston')");
alert(rows.length);
});

看这里：http://jsfiddle.net/drh0mvhz/1

Answer 1

.filter() 允许您进行更复杂的过滤：

var rows = $("#tabCity tr").filter(function() {
    return $(this).find("td:nth-child(2):contains('Smith')").length 
        && $(this).find("td:nth-child(3):contains('Boston')").length;
});

http://jsfiddle.net/bh6t6tf6/

JQuery table 按包含值的倍数搜索行数

JQuery table search number of rows by multiple contains value

jquery

pseudo-class