检查当前时间是否在两个 NSDate 之间 (iOS)

Question

我正在制作一个简单的应用程序来检索有关附近餐馆的信息。我从外部网络服务获取所有数据。每个餐厅对象都有一个 NSDictionary，其中包含该特定餐厅的工作时间。 NSDictionary 的结构如下..

"restaurant_working_hours" =         (
                    {
            close =                 {
                day = 1;
                dayName = Monday;
                time = 0000;
            };
            open =                 {
                day = 1;
                dayName = Monday;
                time = 1500;
            };
        },
                    {
            close =                 {
                day = 2;
                dayName = Tuesday;
                time = 0000;
            };
            open =                 {
                day = 2;
                dayName = Tuesday;
                time = 1500;
            };
        },
                    {
            close =                 {
                day = 3;
                dayName = Wednesday;
                time = 0000;
            };
            open =                 {
                day = 3;
                dayName = Wednesday;
                time = 1500;
            };
        },
                    {
            close =                 {
                day = 4;
                dayName = Thursday;
                time = 0000;
            };
            open =                 {
                day = 4;
                dayName = Thursday;
                time = 1500;
            };
        },
                    {
            close =                 {
                day = 5;
                dayName = Friday;
                time = 0000;
            };
            open =                 {
                day = 5;
                dayName = Friday;
                time = 1500;
            };
        }
    );

在我的应用程序中，我需要一个选项来确定餐厅现在是开门还是关门。以及当天的工作时间，以 12 小时制表示。

我对开发还比较陌生，不知道如何处理这个问题。我可以简单地运行循环并获取所有日期，但这似乎效率低下。

谢谢 :)

Answer 1

您不能使用 NSDate 进行比较。您需要：

获取当前 date/time（如 NSDate）并从午夜提取当前时间（以秒为单位）。
将字典中的时间转换为从午夜算起的秒数。它的格式很奇怪，我假设 1326 将是“下午 1 点后 26 分钟”。

1:

NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *comps = [calendar components:(NSCalendarUnitHour|NSCalendarUnitMinute|NSCalendarUnitSecond)
                                      fromDate:[NSDate date]];
NSInteger nowSeconds = ([comps hour] * 60 * 24) + ([comps minutes] * 60) + [comps seconds];

2:

+ (NSInteger)dictTimeToSeconds:(NSInteger)dictTime
{
    NSInteger hours = dictTime / 100;
    NSInteger minutes = dictTime % 100;
    return (hours * 60 * 24) + (minutes * 60);
}

...

NSArray *workingHours = thatDictionary[@"restaurant_working_hours"];
for (NSDictionary *days in workingHours) {
    NSInteger openTime = [self dictTimeToSeconds:days[@"open"][@"time"]];
    NSInteger closeTime = [self dictTimeToSeconds:days[@"close"][@"time"]];
    if (openTime < nowSeconds && closeTime > nowSeconds) {
        NSLog(@"Open on day %@", days[@"open"][@"dayName"]);
    } else {
        NSLog(@"Closed on day %@", days[@"open"][@"dayName"]);
    }
}

注意：服务器数据的结构不必要地复杂。

Answer 2

感谢@Droppy..这正是我在代码中所做的。

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];
[dateFormatter setDateFormat:@"EEEE"];
NSString *dayName = [dateFormatter stringFromDate:[NSDate date]]

NSString *predicateString = [NSString stringWithFormat:@"close.dayName like '%@'",dayName];
NSPredicate *pred = [NSPredicate predicateWithFormat:predicateString];
NSArray *result = [restaurantWorkingHoursDict filteredArrayUsingPredicate:pred];

NSMutableDictionary *todayDict = [result firstObject];

NSString *closeString = [[todayDict objectForKey:@"close"] objectForKey:@"time"];
NSString *openString = [[todayDict objectForKey:@"open"] objectForKey:@"time"];

NSDateFormatter *outputFormatter = [[NSDateFormatter alloc] init];
[outputFormatter setDateFormat:@"HHmm"];

NSDate *openDate = [outputFormatter dateFromString:openString];
NSDate *closeDate = [outputFormatter dateFromString:closeString];

[outputFormatter setDateFormat:@"h:mm a"];

NSString *openingHour = [outputFormatter stringFromDate:openDate];
NSString *closingHour = [outputFormatter stringFromDate:closeDate];

NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *comps = [calendar components:(NSCalendarUnitHour|NSCalendarUnitMinute|NSCalendarUnitSecond)
                                      fromDate:[NSDate date]];
NSInteger nowSeconds = ([comps hour] * 60 * 60) + ([comps minute] * 60) + [comps second];

NSInteger closeSecond = [self dictTimeToSeconds:[closeString integerValue]];
NSInteger openSecond = [self dictTimeToSeconds:[openString integerValue]];

if (openSecond < nowSeconds && closeSecond > nowSeconds) {
    self.openLebal.text = [NSString stringWithFormat:@"Open Now from:%@ till:%@",openingHour,closingHour];
} else {
    self.openLebal.text = [NSString stringWithFormat:@"Closed Now. Open from:%@ till:%@",openingHour,closingHour];
}

....

- (NSInteger)dictTimeToSeconds:(NSInteger)dictTime{
    NSInteger hours = dictTime / 100;
    NSInteger minutes = dictTime % 100;
    return (hours * 60 * 60) + (minutes * 60);
}

做了一些修改。希望这会对其他人有所帮助。

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