发生内部错误。 [ 无效 access_token,错误代码 43。]

An internal error has occured. [ invalid access_token, error code 43. ]

当我使用 Firebase 的 Facebook 凭据静默登录我的应用程序两次时,它 return 此错误消息。

An internal error has occured. [ invalid access_token, error code 43. ]

我在第一次登录时将 Facebook 令牌保存在 SharedPreferences 中,并在两次登录时获取它,然后使用 FacebookAuthProvider.getCredential(accessToken); 创建凭据。最后,我使用以下代码使用此凭据登录:

private void signInFirebase(AuthCredential credential, final TaskCompleteListener signInListener) {
    FirebaseAuth.getInstance().signInWithCredential(credential)
            .addOnCompleteListener(new OnCompleteListener<AuthResult>() {
                @Override
                public void onComplete(@NonNull Task<AuthResult> task) {
                    if (task.isSuccessful()) {
                        Logger.i(TAG,"Firebase login success.");
                    } else {
                        Logger.e(TAG,"Firebase login failure:"+task.getException().getMessage());
                    }
                }
            });
}

它总是像标题一样打印。 我已经尝试过,但没有用:

1.change Firebase version from 9.0.2 to 9.4.0
2.search error message in Google directly

如何解决这个问题?

Firebase 已在应用重启之间保留用户的登录状态。因此,与其自己保留 Facebook 令牌,不如 monitor whether the user is already authenticated with Firebase.

来自该文档:

FirebaseAuth.getInstance(). addAuthStateListener(new FirebaseAuth.AuthStateListener() {
    @Override
    public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) {
        FirebaseUser user = firebaseAuth.getCurrentUser();
        if (user != null) {
            // User is signed in
            Log.d(TAG, "onAuthStateChanged:signed_in:" + user.getUid());
        } else {
            // User is signed out
            Log.d(TAG, "onAuthStateChanged:signed_out");
        }
        // ...
    }
});