如何知道两个表情符号是否会显示为一个表情符号?
How to know if two emojis will be displayed as one emoji?
表情符号由 2 个 unicodeScalars U+1F44D、U+1F3FC 组成。
如何将其识别为 1 个 'displayed' 表情符号,因为它将在 iOS 上如此显示?
更新 Swift 4 (Xcode 9)
自 Swift 4 起,"Emoji sequence" 被视为单个字素
集群(根据 Unicode 9 标准):
let s = "ab❤️"
print(s.count) // 4
因此不再需要其他解决方法。
(Swift 3 及更早版本的旧答案:)
一个可能的选择是枚举和计算
"composed character sequences" 中的字符串:
let s = "ab❤️"
var count = 0
s.enumerateSubstringsInRange(s.startIndex..<s.endIndex,
options: .ByComposedCharacterSequences) {
(char, _, _, _) in
if let char = char {
count += 1
}
}
print(count) // 4
另一种选择是查找组合字符的范围
给定索引处的序列:
let s = "❤️"
if s.rangeOfComposedCharacterSequenceAtIndex(s.startIndex) == s.characters.indices {
print("This is a single composed character")
}
作为 String
扩展方法:
// Swift 2.2:
extension String {
var composedCharacterCount: Int {
var count = 0
enumerateSubstringsInRange(characters.indices, options: .ByComposedCharacterSequences) {
(_, _, _, _) in count += 1
}
return count
}
var isSingleComposedCharacter: Bool {
return rangeOfComposedCharacterSequenceAtIndex(startIndex) == characters.indices
}
}
// Swift 3:
extension String {
var composedCharacterCount: Int {
var count = 0
enumerateSubstrings(in: startIndex..<endIndex, options: .byComposedCharacterSequences) {
(_, _, _, _) in count += 1
}
return count
}
var isSingleComposedCharacter: Bool {
return rangeOfComposedCharacterSequence(at: startIndex) == startIndex..<endIndex
}
}
示例:
"".composedCharacterCount // 1
"".characters.count // 2
"❤️".composedCharacterCount // 1
"❤️".characters.count // 4
"".composedCharacterCount // 2
"".characters.count // 1
如您所见,Swift 个字符(扩展字素簇)的数量可以多于 或少于
组成字符序列的数量。
表情符号由 2 个 unicodeScalars U+1F44D、U+1F3FC 组成。
如何将其识别为 1 个 'displayed' 表情符号,因为它将在 iOS 上如此显示?
更新 Swift 4 (Xcode 9)
自 Swift 4 起,"Emoji sequence" 被视为单个字素 集群(根据 Unicode 9 标准):
let s = "ab❤️"
print(s.count) // 4
因此不再需要其他解决方法。
(Swift 3 及更早版本的旧答案:)
一个可能的选择是枚举和计算 "composed character sequences" 中的字符串:
let s = "ab❤️"
var count = 0
s.enumerateSubstringsInRange(s.startIndex..<s.endIndex,
options: .ByComposedCharacterSequences) {
(char, _, _, _) in
if let char = char {
count += 1
}
}
print(count) // 4
另一种选择是查找组合字符的范围 给定索引处的序列:
let s = "❤️"
if s.rangeOfComposedCharacterSequenceAtIndex(s.startIndex) == s.characters.indices {
print("This is a single composed character")
}
作为 String
扩展方法:
// Swift 2.2:
extension String {
var composedCharacterCount: Int {
var count = 0
enumerateSubstringsInRange(characters.indices, options: .ByComposedCharacterSequences) {
(_, _, _, _) in count += 1
}
return count
}
var isSingleComposedCharacter: Bool {
return rangeOfComposedCharacterSequenceAtIndex(startIndex) == characters.indices
}
}
// Swift 3:
extension String {
var composedCharacterCount: Int {
var count = 0
enumerateSubstrings(in: startIndex..<endIndex, options: .byComposedCharacterSequences) {
(_, _, _, _) in count += 1
}
return count
}
var isSingleComposedCharacter: Bool {
return rangeOfComposedCharacterSequence(at: startIndex) == startIndex..<endIndex
}
}
示例:
"".composedCharacterCount // 1
"".characters.count // 2
"❤️".composedCharacterCount // 1
"❤️".characters.count // 4
"".composedCharacterCount // 2
"".characters.count // 1
如您所见,Swift 个字符(扩展字素簇)的数量可以多于 或少于 组成字符序列的数量。