从其 url 下载图像并直接上传到 AWS

Download an image from its url and directly upload it to AWS

我的问题找不到满意的答案。给定一张图片 url,我想下载它(不将其保存到磁盘)并立即将其上传到 AWS Bucket。这是我的代码:

  self.downloadImage = function(url){
        let response = HTTP.get(url, {
            encoding:null // for binary
        })
        if (!response.headers['content-type'].split('/')[0] == 'image'){
            throw new Error("not an image")
        }
        return {
            data : response.content,
            contentType : response.headers['content-type']
        }
    }

    self.uploadImage = function(websiteName, imgUrl, callback){
        // we retrieve the image
        let image = downloadImage(imgUrl)
        let imageName = self.extractImageName(imgUrl)
        let filename = 'img/' +websiteName + "/" + imageName
        let newUrl = `https://s3.${Meteor.settings.AWS.REGION}.amazonaws.com/${Meteor.settings.S3.BUCKET_NAME}/${filename}`
        // makes the async function sync like
        let putObjectSync = Meteor.wrapAsync(s3Client.putObject, s3Client)
        try{
            let res = putObjectSync({
                Body: image.data,
                ContentType : image.contentType,
                ContentEncoding: 'base64',
                Key: filename,
                ACL:'public-read',
                Bucket: Meteor.settings.S3.BUCKET_NAME
            })
            return newUrl
        } catch(e) {
            return null
        }
    }

一切正常,除了图像似乎已损坏。到目前为止我试过了:

仍然损坏。我感觉非常接近解决方案,因为图像具有正确的类型和文件大小,但仍然无法在浏览器或我的计算机上打印。关于如何正确 encode/retrieve 数据的任何想法?

好的我自己找到了答案:

aldeed:meteor 允许向 get 请求添加 responseType 参数。我们只需要将此选项设置为 buffer,以便我们将数据作为缓冲区获取。然后我们简单的给这个buffer,不做任何转换,作为上传函数的Body