如何在 if/elif 之后打印相同的 randomint？

Question

我想让 randint 每次执行时都像 if/elif 语句一样打印出来，而不返回新的整数。还有另一种方法可以不用在 while 语句之后写那么多代码吗？

from random import *
def randomchance():
    return randint(1, 100)
def randomknife():
    return randint(1, 8)
skins = ['blue', 'purple', 'pink', 'red']
knives = ['karambit', 'flip', 'bowie', 'butterfly', 'm9 bayonet', 'bayonet', 'daggers', 'falchion']
print 'Welcome to CS GO case lottery'
for skin in skins:
    print "Available", skin,
for knife in knives:
    print "Available", knife,
print '(blue = common, purple = uncommon, pink = rare, red = epic)'
keys = 10
while keys >0:
    resp=raw_input("Enter 'yes' to open a case: ")
    if (resp == str('yes') or resp == str('Yes')):
        print 'Opening case...'
        if (randomchance() >= 35):
            print 'You\'ve won a', skins[0]
        elif (randomchance() >= 20):
            print 'You\'ve won a', skins[1]
        elif (randomchance() >= 10):
            print 'You\'ve won a', skins[2]
        elif (randomchance() >= 5):
            print 'You\'ve won a', skins[3]
        elif (randomchance() >= 1):
            if randomknife == 1:
                print 'You\'ve won a', knifes[0]
            elif randomknife() == 2:
                print 'You\'ve won a', knifes[1]
            elif randomknife() == 3:
                print 'You\'ve won a', knifes[2]
            elif randomknife() == 4:
                print 'You\'ve won a', knifes[3]
            elif randomknife() == 5:
                print 'You\'ve won a', knifes[4]
            elif randomknife() == 6:
                print 'You\'ve won a', knifes[5]
            elif randomknife() == 7:
                print 'You\'ve won a', knifes[6]
            elif randomknife() == 8:
                print 'You\'ve won a', knifes[7]
        keys -= 1        

    elif(resp == str('no') or resp==str('No')):
        resp1=raw_input('Would you like to exit? Enter no for exit: ')
        if resp1 == 'no' or "No":
            exit()
    else:
        print "Yes or No. Answers only"
else:
    print 'You\'ve run out of keys!'

Answer 1

尝试在 if/else 语句之前保存到变量：

number = randomchance();
if (number >= 35): print 'you select a ', number

Answer 2

我会这样做：

knives = ['karambit', 'flip', 'bowie', 'butterfly', 'm9 bayonet', 'bayonet', 'daggers', 'falchion']
skins = ['blue'] * 35 + ['purple'] * 20 + ['pink'] * 10 + ['red'] * 5 + [0]
skin = random.choice(skins)
print "You won a " + skin + " skin" if skin else "You won a " + random.choice(knives) + " knife"

Answer 3

@Konstantin 对如何在测试所有条件之前只选择一次随机数给出了正确答案。

关于你的第二个问题（如何使用更少的代码来测试所有条件），请看下面我的rewrite/cleanup。特别是，我使用random.choice来挑选一把刀，我使用了一系列阈值（35、20等）来挑选皮肤。

我还修复了一些错误，比如你的 if resp1 == 'no' or "No": 应该是 if resp1 == 'no' or resp1 == "No":（但我用的是 resp1.lower()）。

我受不了 'Would you like to exit? Enter no for exit: '，所以我 "yes" 退出了。 :-)

import random

skins = ['blue', 'purple', 'pink', 'red']
knives = ['karambit', 'flip', 'bowie', 'butterfly', 'm9 bayonet', 'bayonet', 'daggers', 'falchion']

print 'Welcome to CS GO case lottery'

print "Available skins: %s" % ', '.join(skins)
print "Available knives: %s" % ', '.join(knives)
print '(blue = common, purple = uncommon, pink = rare, red = epic)'

for _ in range(10):
    resp = raw_input("Enter 'yes' to open a case: ")
    while resp.lower() != 'yes':
        if resp.lower() == 'no':
            if raw_input('Would you like to exit? ').lower() == 'yes':
                exit()
        else:
            print "Yes or no answers only."
        resp = raw_input("Enter 'yes' to open a case: ")

    print 'Opening case...'

    chance = random.randint(1, 100)

    for i, n in enumerate([35, 20, 10, 5]):
        if chance >= n:
            print "You've won a %s skin." % skins[i]
            break

    if chance < 5:
        print "You've won a %s knife." % random.choice(knives)

print "You've run out of keys!"

如何在 if/elif 之后打印相同的 randomint？

how to print same randomint after if/elif?

python-2.6