使用 bash 从列化数据中获取数据

Question

我有一组来自脚本的 git 数据：

objects=`git verify-pack -v .git/objects/pack/pack-*.idx | grep -v chain | sort -k3nr | head`

echo "All sizes are in kB's. The pack column is the size of the object, compressed, inside the pack file."

output="size,pack,SHA,location"
for y in $objects
do
    # extract the size in bytes
    size=$((`echo $y | cut -f 5 -d ' '`/1024))
    # extract the compressed size in bytes
    compressedSize=$((`echo $y | cut -f 6 -d ' '`/1024))
    # extract the SHA
    sha=`echo $y | cut -f 1 -d ' '`
    # find the objects location in the repository tree
    other=`git rev-list --all --objects | grep $sha`
    #lineBreak=`echo -e "\n"`
    output="${output}\n${size},${compressedSize},${other}"
done

打印列化的数据以便更好地阅读：

echo -e $output | column -t -s ', '

如何访问第一行的位置并将其保存到变量中？有任何想法吗？谢谢

Answer 1

你可以试试：

output="size,pack,SHA,location"
firstRowLocation=""
for y in $objects
   # ... snip ...
   output="${output}\n${size},${compressedSize},${other}"
   [ "$firstRowLocation" ] || firstRowLocation=$other
done

使用 bash 从列化数据中获取数据

Get data from columnized data with bash

bash

git-bash