Google Android 人员错误 Status{statusCode=NETWORK_ERROR, resolution=null}

Question

很好 day.I 我正在尝试调用 api method.All 一切顺利，登录屏幕正在根据其圈子的请求呈现给用户，我一收到就繁荣试图从圈子中获取人员列表总是出错！

Status{statusCode=NETWORK_ERROR, resolution=null}

我不知道是什么原因造成的，通过谷歌搜索，我发现没有任何东西更接近我的问题，所以很糟糕 post 我如何调用此方法的代码。 下面是我如何构建和调用它。

 public synchronized GoogleApiClient buildGoogleApiClient(final Activity activity) {
    GoogleSignInOptions gGoogleSignInOptions = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
            .requestScopes(new Scope(Scopes.PROFILE))
            .requestScopes(new Scope(Scopes.PLUS_LOGIN))
            .requestProfile()
            .requestEmail()
            .build();

    mGoogleApiClient = new GoogleApiClient.Builder(activity)
            .addApi(Auth.GOOGLE_SIGN_IN_API, gGoogleSignInOptions)
            .addConnectionCallbacks(new GoogleApiClient.ConnectionCallbacks() {
                @Override
                public void onConnected(@Nullable Bundle bundle) {
                    Plus.PeopleApi.loadVisible(mGoogleApiClient, "me").setResultCallback(new ResultCallbacks<People.LoadPeopleResult>() {
                        @Override
                        public void onSuccess(@NonNull People.LoadPeopleResult loadPeopleResult) {
                            Toast.makeText(activity, "", Toast.LENGTH_SHORT).show();
                            Person person = loadPeopleResult.getPersonBuffer().get(0);
                            Log.d("fasfafasfsafasfas", "onSuccess: " + person);
                        }

                        @Override
                        public void onFailure(@NonNull Status status) {
                            if (status.hasResolution()) {
                                try {
                                    // !!!
                                    status.startResolutionForResult(activity, 100);
                                } catch (IntentSender.SendIntentException e) {
                                    mGoogleApiClient.connect();
                                }
                            }
                            Log.d("fasfafasfsafasfas", "onFailure: " + status);
                        }

                    });

                }

                @Override
                public void onConnectionSuspended(int i) {
                    Toast.makeText(activity, "fail", Toast.LENGTH_SHORT).show();
                }
            })
            .addApi(Plus.API)
            .build();
    mGoogleApiClient.connect(GoogleApiClient.SIGN_IN_MODE_OPTIONAL);
    return mGoogleApiClient;
}

它总是进入 onFailure 回调并出现网络错误。我不知道我输入的错误... 这是清单中需要的权限

    <uses-permission android:name="android.permission.GET_ACCOUNTS" />
<uses-permission android:name="android.permission.AUTHENTICATE_ACCOUNTS" />
<uses-permission android:name="android.permission.READ_PROFILE" />

请告诉我我的代码有什么问题？

Answer 1

如果有人在这里遇到同样的问题是solution.You在获取圈子时不需要指定"me"，同时像这样指定NULL

  Plus.PeopleApi.loadVisible(mGoogleApiClient, null
                    ).setResultCallback(new ResultCallbacks<People.LoadPeopleResult>() {
                        @Override
                        public void onSuccess(@NonNull People.LoadPeopleResult loadPeopleResult) {
                            int personCount = loadPeopleResult.getPersonBuffer().getCount();
                            Log.d("fasfafasfsafasfas", "onSuccess: " + personCount);
                            for (int i = 0; i < personCount; i++) {
                                Person eachPerson = loadPeopleResult.getPersonBuffer().get(i);
                                Log.d("fasfafasfsafasfas", "onSuccess: " + eachPerson.getImage().getUrl());
                            }
                        }

                        @Override
                        public void onFailure(@NonNull Status status) {
                            if (status.hasResolution()) {
                                try {
                                    status.startResolutionForResult(activity, requestCode);
                                } catch (IntentSender.SendIntentException e) {
                                    mGoogleApiClient.connect();
                                }
                            }
                            Log.d("fasfafasfsafasfas", "onFailure: " + status);
                        }

                    });