在一个函数中以编程方式在彼此之上呈现两个 UIViewController

Present two UIViewControllers on top of each other programmatically in one function

我正在尝试展示 (1) ScrollViewController,然后展示 (2) ImagePicker。但是,只有 ScrollViewController 出现,后面的 ImagePicker 没有出现。

就个人而言,下面的代码工作正常,只是当一个跟随另一个时,它不起作用。我试过在完成处理程序中包含一个,仍然没有成功。

没有错误显示,除了,当序列发生时,Xcode 调试区域显示但完全空白,没有错误消息或警告。

问题:

What exactly is going on here that I'm missing? Why aren't both being presented? How can I ensure both the ScrollViewController and ImagePicker are displayed, one after the other?

(1) 滚动视图控制器:

 let storyboard = UIStoryboard(name: "Main", bundle: nil)
 let vc = storyboard.instantiateViewControllerWithIdentifier("ScrollViewControllerID") as! ScrollViewController
 self.presentViewController(vc, animated: true, completion: nil)

(2) ImagePicker:

 let imagePicker = MyImagePickerController()
 imagePicker.delegate = self
 imagePicker.sourceType = .PhotoLibrary
 imagePicker.allowsEditing = false
 imagePicker.modalTransitionStyle = UIModalTransitionStyle.CoverVertical
 self.presentViewController(imagePicker, animated: true, completion: nil)

一个视图控制器一次只能呈现一个控制器。事实上,有一个 属性: presentedViewController: UIViewController? 暗示了这一点。协调这些行动:

一个。仅展示来自您的基地 VC.

first VC

乙。在第一个演示调用的完成处理程序中,让 second VC 呈现最后一个位于顶部的:

let storyboard = UIStoryboard(name: "Main", bundle: nil)
let vc = storyboard.instantiateViewControllerWithIdentifier("ScrollViewControllerID") as! ScrollViewController
self.presentViewController(vc, animated: true) {
    let imagePicker = MyImagePickerController()
    imagePicker.delegate = self
    imagePicker.sourceType = .PhotoLibrary
    imagePicker.allowsEditing = false
    imagePicker.modalTransitionStyle = UIModalTransitionStyle.CoverVertical
    vc.presentViewController(imagePicker, animated: true, completion: nil)
}