python 中的多级 JSON 差异

Question

请link我回答如果已经回答了，我的问题是我想获得无序的多级差异json。

x=json.loads('''[{"y":2,"x":1},{"x":3,"y":4}]''')
y=json.loads('''[{"x":1,"y":2},{"x":3,"y":4}]''')
z=json.loads('''[{"x":3,"y":4},{"x":1,"y":2}]''')

import json_tools as jt
import json_delta as jd


print jt.diff(y,z)
print jd.diff(y,z)
print y==z
print x==y

输出是

[{'prev': 2, 'value': 4, 'replace': u'/0/y'}, {'prev': 1, 'value': 3, 'replace': u'/0/x'}, {'prev': 4, 'value': 2, 'replace': u'/1/y'}, {'prev': 3, 'value': 1, 'replace': u'/1/x'}]
[[[2], {u'y': 2, u'x': 1}], [[0]]]
False
True

我的问题是如何让 y 和 z 相等，或者是否存在取决于 JSON 的非顺序的实际差异。

一种无序的字典列表，但我正在寻找 list/dict 的 list/dictionaries 字典的水平证明...

Answer 1

使用以下函数部分解决了它

def diff(prev,lat):
    p=prev
    l=lat


    prevDiff = []
    latDiff = []

    for d1 in p[:]:
        flag = False
        for d2 in l:
            if len(set(d1.items()) ^ set(d2.items())) == 0:
                p.remove(d1)
                l.remove(d2)
                flag = True
                break
        if not flag:
            prevDiff.append(d1)
            p.remove(d1)

    prevDiff = prevDiff + p
    latDiff = latDiff + l

    resJSONdata=[]
    if len(prevDiff) != 0:
        resJSONdata.append({'prevCount':len(prevDiff)})
        resJSONdata.append({'prev':prevDiff})
    if len(latDiff) != 0:
        resJSONdata.append({'latestCount':len(latDiff)})
        resJSONdata.append({'latest':latDiff})

#     return json.dumps(resJSONdata,indent = 4,sort_keys=True)
    return resJSONdata

它并没有递归地逐级进行，但为了我的目的，这解决了问题

Answer 2

看看这个 python 库 jsondiff ，它将帮助您识别差异

import json

import jsondiff

json1 = json.loads(
    '{"isDynamic": false, "name": "", "value": "SID:<sid>", "description": "instance","argsOrder": 1,"isMultiSelect": false}')

json2 = json.loads(
    '{ "name": "", "value": "SID:<sid>","isDynamic": false, "description": "instance","argsOrder": 1,"isMultiSelect": false}')

res = jsondiff.diff(json1, json2)
if res:
    print("Diff found")
else:
    print("Same")

Answer 3

是的！你可以用开箱即用的 jycm which has a rendering tool 来区分它。

它使用 LCS、Edit distance 和 Kuhn–Munkres 来区分数组。

这是一个通用示例，其中包含集合中的集合和某些集合中的值更改

from jycm.helper import make_ignore_order_func
from jycm.jycm import YouchamaJsonDiffer

left = {
    "set_in_set": [
        {
            "id": 1,
            "label": "label:1",
            "set": [
                1,
                5,
                3
            ]
        },
        {
            "id": 2,
            "label": "label:2",
            "set": [
                4,
                5,
                6
            ]
        }
    ]
}

right = {
    "set_in_set": [
        {
            "id": 2,
            "label": "label:2",
            "set": [
                6,
                5,
                4
            ]
        },
        {
            "id": 1,
            "label": "label:1111",
            "set": [
                3,
                2,
                1
            ]
        }
    ]
}

ycm = YouchamaJsonDiffer(left, right, ignore_order_func=make_ignore_order_func([
    "^set_in_set$",
    "^set_in_set->\[\d+\]->set$"
]))

ycm.diff()

expected = {
    'list:add': [
        {'left': '__NON_EXIST__', 'right': 2, 'left_path': '', 'right_path': 'set_in_set->[1]->set->[1]'}
    ],
    'list:remove': [
        {'left': 5, 'right': '__NON_EXIST__', 'left_path': 'set_in_set->[0]->set->[1]', 'right_path': ''}
    ],
    'value_changes': [
        {'left': 'label:1', 'right': 'label:1111', 'left_path': 'set_in_set->[0]->label',
         'right_path': 'set_in_set->[1]->label', 'old': 'label:1', 'new': 'label:1111'}
    ]
}

assert ycm.to_dict(no_pairs=True) == expected

你可以设置no_pairs=False来得到所有的对。这是一个呈现的例子：

至于这里的例子，你可以这样使用：

from jycm.helper import make_ignore_order_func
from jycm.jycm import YouchamaJsonDiffer

left = {
    "data": [{"x": 1, "y": 2}, {"x": 3, "y": 4}]
}

right = {
    "data": [{"x": 3, "y": 4}, {"x": 1, "y": 2}]
}

ycm = YouchamaJsonDiffer(left, right, ignore_order_func=make_ignore_order_func([
    "^data",
]))

ycm.diff()

assert ycm.to_dict(no_pairs=True) == {}

奖金，你的值被中断为平原上的坐标，你甚至可以定义一个运算符来判断两个点是否匹配！（然后比较它们的值）

代码如下：

from typing import Tuple

from jycm.helper import make_ignore_order_func
from jycm.jycm import YouchamaJsonDiffer
from jycm.operator import BaseOperator
import math

left = {
    "data": [
        {"x": 1, "y": 1},
        {"x": 10, "y": 10},
        {"x": 100, "y": 100}
    ]
}

right = {
    "data": [
        {"x": 150, "y": 150},
        {"x": 10, "y": 11},
        {"x": 2, "y": 3}
    ]
}


class L2DistanceOperator(BaseOperator):
    __operator_name__ = "operator:l2distance"
    __event__ = "operator:l2distance"

    def __init__(self, path_regex, distance_threshold):
        super().__init__(path_regex=path_regex)
        self.distance_threshold = distance_threshold

    def diff(self, level: 'TreeLevel', instance, drill: bool) -> Tuple[bool, float]:
        distance = math.sqrt(
            (level.left["x"] - level.right["x"]) ** 2 + (level.left["y"] - level.right["y"]) ** 2
        )
        info = {
            "distance": distance,
            "distance_threshold": self.distance_threshold,
            "pass": distance < self.distance_threshold
        }

        if not drill:
            instance.report(self.__event__, level, info)
            return False, 1 if info["pass"] else 0
        return True, 1 if info["pass"] else 0


ycm = YouchamaJsonDiffer(left, right, ignore_order_func=make_ignore_order_func([
    "^data$",
]), custom_operators=[
    L2DistanceOperator("^data->\[.*\]$", 10),
])

ycm.diff()

expected = {
    'just4vis:pairs': [
        {'left': 1, 'right': 2, 'left_path': 'data->[0]->x', 'right_path': 'data->[2]->x'},
        {'left': {'x': 1, 'y': 1}, 'right': {'x': 2, 'y': 3}, 'left_path': 'data->[0]',
         'right_path': 'data->[2]'},
        {'left': 1, 'right': 3, 'left_path': 'data->[0]->y', 'right_path': 'data->[2]->y'},
        {'left': {'x': 1, 'y': 1}, 'right': {'x': 2, 'y': 3}, 'left_path': 'data->[0]',
         'right_path': 'data->[2]'},
        {'left': {'x': 1, 'y': 1}, 'right': {'x': 2, 'y': 3}, 'left_path': 'data->[0]',
         'right_path': 'data->[2]'}
    ],
    'list:add': [
        {'left': '__NON_EXIST__', 'right': {'x': 150, 'y': 150}, 'left_path': '', 'right_path': 'data->[0]'}
    ],
    'list:remove': [
        {'left': {'x': 100, 'y': 100}, 'right': '__NON_EXIST__', 'left_path': 'data->[2]', 'right_path': ''}
    ],
    'operator:l2distance': [
        {'left': {'x': 1, 'y': 1}, 'right': {'x': 2, 'y': 3}, 'left_path': 'data->[0]',
         'right_path': 'data->[2]', 'distance': 2.23606797749979, 'distance_threshold': 10,
         'pass': True},
        {'left': {'x': 10, 'y': 10}, 'right': {'x': 10, 'y': 11}, 'left_path': 'data->[1]',
         'right_path': 'data->[1]', 'distance': 1.0, 'distance_threshold': 10,
         'pass': True}
    ],
    'value_changes': [
        {'left': 1, 'right': 2, 'left_path': 'data->[0]->x', 'right_path': 'data->[2]->x', 'old': 1, 'new': 2},
        {'left': 1, 'right': 3, 'left_path': 'data->[0]->y', 'right_path': 'data->[2]->y', 'old': 1, 'new': 3},
        {'left': 10, 'right': 11, 'left_path': 'data->[1]->y', 'right_path': 'data->[1]->y', 'old': 10, 'new': 11}
    ]
}
assert ycm.to_dict() == expected

如您所见，jycm 报告了点 {'x': 150, 'y': 150} 和 {'x': 100, 'y': 100} 的添加和删除距离太远（超过 10）并且其他两个点的值发生变化。

P.S。渲染器演示

python 中的多级 JSON 差异

Multilevel JSON diff in python

python

json

compare

diff

unordered