Index.cond 不重新排列格子中的面板

Question

我正在按照书本 "R in action" P389 示例在以下格图中排列 hist 面板：

library(lattice)
graph1 <- histogram(~ height | voice.part, data = singer,
                    main = "Heights of Choral Singers by Voice Part")
graph2 <- densityplot(~ height, data = singer, group = voice.part,
                      plot.points = FALSE, auto.key = list(columns = 4))
plot(graph1, position=c(0, .3, 1, 1))
plot(graph2, position=c(0, 0, 1, .3), newpage = FALSE)

按照书中的说明，我使用index.cond来改变图表的顺序，比如

plot(graph1, position = c(0, .3, 1, 1),
     index.cond = list(c(2, 4, 6, 8, 1, 3, 5, 7)))

但图中的顺序没有改变。谁能帮我这个？我还注意到 index.cond 不在 ?plot

的帮助下

Answer 1

"index.cond"，因为 ?xyplot 中描述的其他参数要么传递给创建 "trellis" 对象的函数，要么传递给 update 方法。所以，在这种情况下，你可以

通过将 "index.cond" 传递给 histogram 创建 "graph1":

histogram(~ height | voice.part, data = singer, 
          main = "Heights of Choral Singers by Voice Part", 
          index.cond = list(c(2, 4, 6, 8, 1, 3, 5, 7)))

, 使用 update:

update(graph1, index.cond = list(c(2, 4, 6, 8, 1, 3, 5, 7)))

或使用"[":

graph1[c(2, 4, 6, 8, 1, 3, 5, 7)]

Index.cond 不重新排列格子中的面板

Index.cond does not rearrange the panels in lattice

graphics

r

lattice