Impala: 所有 DISTINCT 聚合函数需要有相同的参数集

Question

我的 Impala 查询中出现以下错误：

select 
   upload_key, 
   max(my_timestamp) as upload_time, 
   max(color_key) as max_color_fk, 
   count(distinct color_key) as color_count, 
   count(distinct id) as toy_count 
from upload_table 
group by upload_key

得到错误：

AnalysisException: all DISTINCT aggregate functions need to have the same set of parameters as count(DISTINCT color_key); deviating function: count(DISTINCT id)

我不确定为什么会出现此错误。我所做的是针对每个组（按 upload_key 分组），我试图计算有多少 distinct id 以及有多少 distinct color_key。
有人知道吗

Answer 1

错误消息表明 DISTINCT 仅允许在一个 列 [组合] 上，但您尝试两个，color_key& id.解决方法是先选择两个 Select，然后再连接：

select
   t1.upload_key,
   t1.upload_time,
   t1.max_color_fk,
   t1.color_count,
   t2.toy_count
from
 (
   select 
      upload_key, 
      max(my_timestamp) as upload_time, 
      max(color_key) as max_color_fk, 
      count(distinct color_key) as color_count
   from upload_table 
   group by upload_key
 ) as t1
join
 (
   select 
      upload_key
      count(distinct id) as toy_count 
   from upload_table 
   group by upload_key
 ) as t2
on t1. upload_key = t2.upload_key

Impala: 所有 DISTINCT 聚合函数需要有相同的参数集

Impala: all DISTINCT aggregate functions need to have the same set of parameters

sql

hdfs

impala