Jolt 变换未命名数组
Jolt transform unnamed array
使用来自 jsonplaceholder.com 的示例 json 响应,我想对返回的未命名数组执行 Jolt 转换。
但是,使用 jolt demo 我只能在命名数组(本例中为 "records")并用花括号括起来后转换数组。像这样:
Json 输入:
{
"records": [
{
"id": 1,
"name": "Leanne Graham",
"username": "Bret",
"email": "Sincere@april.biz",
"address": {
"street": "Kulas Light",
"suite": "Apt. 556",
"city": "Gwenborough",
"zipcode": "92998-3874",
"geo": {
"lat": "-37.3159",
"lng": "81.1496"
}
},
"phone": "1-770-736-8031 x56442",
"website": "hildegard.org",
"company": {
"name": "Romaguera-Crona",
"catchPhrase": "Multi-layered client-server neural-net",
"bs": "harness real-time e-markets"
}
},
{
"id": 2,
"name": "Ervin Howell",
"username": "Antonette",
"email": "Shanna@melissa.tv",
"address": {
"street": "Victor Plains",
"suite": "Suite 879",
"city": "Wisokyburgh",
"zipcode": "90566-7771",
"geo": {
"lat": "-43.9509",
"lng": "-34.4618"
}
},
"phone": "010-692-6593 x09125",
"website": "anastasia.net",
"company": {
"name": "Deckow-Crist",
"catchPhrase": "Proactive didactic contingency",
"bs": "synergize scalable supply-chains"
}
}
]
}
颠簸规格:
[
{
"operation": "shift",
"spec": {
"records": {
"*": {
"id": "records[&1].user-id",
"username": "records[&1].user-username",
"email": "records[&1].user-email",
"address": {
"street": "records[&2].user-street",
"suite": "records[&2].user-suite",
"city": "records[&2].user-city",
"zipcode": "records[&2].user-zipcode"
}
}
}
}
}
]
我的示例的目标是展平响应中返回的对象层次结构,同时保持基本的 [{}, {}, ...]
结构。
当输入是一个未命名的 json 数组时,如何实现这一点?
发帖后才知道答案...
这是我为任何感兴趣的人修改的规范:
[
{
"operation": "shift",
"spec": {
"*": {
"id": "[&1].user-id",
"username": "[&1].user-username",
"email": "[&1].user-email",
"address": {
"street": "[&2].user-street",
"suite": "[&2].user-suite",
"city": "[&2].user-city",
"zipcode": "[&2].user-zipcode"
}
}
}
}
]
声明spec("spec": { "*": { "
)后简单匹配,然后用[&1]
、[&2]
等访问无名数组
下面一个有效,但没有变平
[
{
"operation": "shift",
"spec": {
"*": {
"*": {
"id": "[&1].user-id",
"username": "[&1].user-username",
"email": "[&1].user-email",
"address": {
"street": "[&2].user-street",
"suite": "[&2].user-suite",
"city": "[&2].user-city",
"zipcode": "[&2].user-zipcode"
}
}
}
}
}
]
使用来自 jsonplaceholder.com 的示例 json 响应,我想对返回的未命名数组执行 Jolt 转换。
但是,使用 jolt demo 我只能在命名数组(本例中为 "records")并用花括号括起来后转换数组。像这样:
Json 输入:
{
"records": [
{
"id": 1,
"name": "Leanne Graham",
"username": "Bret",
"email": "Sincere@april.biz",
"address": {
"street": "Kulas Light",
"suite": "Apt. 556",
"city": "Gwenborough",
"zipcode": "92998-3874",
"geo": {
"lat": "-37.3159",
"lng": "81.1496"
}
},
"phone": "1-770-736-8031 x56442",
"website": "hildegard.org",
"company": {
"name": "Romaguera-Crona",
"catchPhrase": "Multi-layered client-server neural-net",
"bs": "harness real-time e-markets"
}
},
{
"id": 2,
"name": "Ervin Howell",
"username": "Antonette",
"email": "Shanna@melissa.tv",
"address": {
"street": "Victor Plains",
"suite": "Suite 879",
"city": "Wisokyburgh",
"zipcode": "90566-7771",
"geo": {
"lat": "-43.9509",
"lng": "-34.4618"
}
},
"phone": "010-692-6593 x09125",
"website": "anastasia.net",
"company": {
"name": "Deckow-Crist",
"catchPhrase": "Proactive didactic contingency",
"bs": "synergize scalable supply-chains"
}
}
]
}
颠簸规格:
[
{
"operation": "shift",
"spec": {
"records": {
"*": {
"id": "records[&1].user-id",
"username": "records[&1].user-username",
"email": "records[&1].user-email",
"address": {
"street": "records[&2].user-street",
"suite": "records[&2].user-suite",
"city": "records[&2].user-city",
"zipcode": "records[&2].user-zipcode"
}
}
}
}
}
]
我的示例的目标是展平响应中返回的对象层次结构,同时保持基本的 [{}, {}, ...]
结构。
当输入是一个未命名的 json 数组时,如何实现这一点?
发帖后才知道答案...
这是我为任何感兴趣的人修改的规范:
[
{
"operation": "shift",
"spec": {
"*": {
"id": "[&1].user-id",
"username": "[&1].user-username",
"email": "[&1].user-email",
"address": {
"street": "[&2].user-street",
"suite": "[&2].user-suite",
"city": "[&2].user-city",
"zipcode": "[&2].user-zipcode"
}
}
}
}
]
声明spec("spec": { "*": { "
)后简单匹配,然后用[&1]
、[&2]
等访问无名数组
下面一个有效,但没有变平
[
{
"operation": "shift",
"spec": {
"*": {
"*": {
"id": "[&1].user-id",
"username": "[&1].user-username",
"email": "[&1].user-email",
"address": {
"street": "[&2].user-street",
"suite": "[&2].user-suite",
"city": "[&2].user-city",
"zipcode": "[&2].user-zipcode"
}
}
}
}
}
]