R：标题用 par() 减半

Question

我有这个数字：

require(corrplot)
par(oma=c(0,0,2,0), mfrow = c(1, 3))
for (country in c("Italy","Germany","Afghanistan")) {
  corrplot.mixed(cor(data.frame(v1=rnorm(40),
                                v2=rnorm(40),
                                v3=rnorm(40),
                                v4=rnorm(40),
                                v5=rnorm(40),
                                v6=rnorm(40),
                                v7=rnorm(40),
                                v8=rnorm(40)), use="pairwise.complete.obs"),
                 main=country)
}
par(mfrow = c(1, 1))

生成的标题减半：

在 this answer 之后我设置了 oma=c(0,0,2,0) 但它不会影响结果。我不确定我应该修改哪个边距。我查看了?par，修改了"oma"、"omd"、"omi"、"mai"、"mar"，没有结果。

Answer 1

我发现将 mar 参数传递给 corrplot 是有效的：

    png(height=300,width=600);par(oma=c(0,0,2,0), mfrow = c(1, 3))
for (country in c("Italy","Germany","Afghanistan")) {
  corrplot.mixed(cor(data.frame(v1=rnorm(40),
                                v2=rnorm(40),
                                v3=rnorm(40),
                                v4=rnorm(40),
                                v5=rnorm(40),
                                v6=rnorm(40),
                                v7=rnorm(40),
                                v8=rnorm(40)), use="pairwise.complete.obs"),
                 main=country, mar=c(0,0,2,0))
};dev.off()

R：标题用 par() 减半

R: Titles cut in half with par()

r

plot

r-corrplot