如何在 SQL 服务器的 JOIN 中使用 COLLATE？

Question

我正在尝试连接两个表，但出现此错误：

Msg 468, Level 16, State 9, Line 8 Cannot resolve the collation conflict between "SQL_Latin1_General_CP1_CI_AS" and "Latin1_General_CI_AS" in the equal to operation.

这是我使用的代码：

 SELECT *

  FROM [FAEB].[dbo].[ExportaComisiones] AS f

  JOIN [zCredifiel].[dbo].[optPerson] AS p

  ON (p.vTreasuryId = f.RFC) COLLATE Latin1_General_CI_AS

我知道错了，下划线COLLATE。我不知道如何应用它。

Answer 1

正确的语法如下所示。参见 MSDN。

SELECT *
  FROM [FAEB].[dbo].[ExportaComisiones] AS f
  JOIN [zCredifiel].[dbo].[optPerson] AS p

  ON p.vTreasuryId COLLATE Latin1_General_CI_AS = f.RFC COLLATE Latin1_General_CI_AS

Answer 2

作为一般规则，您可以使用 Database_Default 排序规则，因此您无需确定使用哪一个。但是，我强烈建议阅读 Simons Liew 的优秀文章 Understanding the COLLATE DATABASE_DEFAULT clause in SQL Server

SELECT *
  FROM [FAEB].[dbo].[ExportaComisiones] AS f
  JOIN [zCredifiel].[dbo].[optPerson] AS p
  ON (p.vTreasuryId = f.RFC) COLLATE Database_Default

如何在 SQL 服务器的 JOIN 中使用 COLLATE？

How to use the COLLATE in a JOIN in SQL Server?

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join

collate