在自定义 ListView 中不可点击的 Spannable 字符串
Spannable string not clickable in a custom ListView
在 ListView
中的一行上使用 Button 并且能够使单行 Spannable 和来自数据库的数据但是当我点击它时它没有响应点击这里是我的代码来自 MyAdapter Class
我在哪里输入数据库中的值到 Listview
public View getView(int i, View view, ViewGroup viewGroup) {
Realm realm=Realm.getDefaultInstance();
Word toEdit = realm.where(Word.class)
.equalTo("id", 10).findFirst();
int id_to_seperate=toEdit.getLang();
LayoutInflater inflater= (LayoutInflater) Main.context.getSystemService(Main.context.LAYOUT_INFLATER_SERVICE);
View row= inflater.inflate(R.layout.layout,viewGroup,false);
TextView word= (TextView) row.findViewById(R.id.word_name);
TextView meaning= (TextView) row.findViewById(R.id.word_define);
Word temp=list.get(i);
int idz=temp.getId();
word.setText(temp.getWord());
if(id_to_seperate==idz){
String span[] = temp.getMeaning().substring(1).split(" ") ;
SpannableString ss = new SpannableString(temp.getMeaning().substring(1));
ClickableSpan spans[] = new ClickableSpan[span.length];
for(int spanCount = 0 ; spanCount < span.length ; spanCount++){
spans[spanCount] = new ClickableSpan() {
@Override
public void onClick(View textView) {
TextView v = (TextView)textView ;
String text = v.getText().toString() ;
Log.d("View" , text);
}
};
}
int start = 0 ;
int end =0;
try {
for(int spanCount = 0 ; spanCount <span.length ; spanCount++){
if(spanCount==0) {
end += span[spanCount].length();
}else{
end += span[spanCount].length()+1;
}
ss.setSpan(spans[spanCount], start, end , Spanned.SPAN_EXCLUSIVE_EXCLUSIVE);
start += span[spanCount].length()+1;
}
} catch (Exception e) {
e.printStackTrace();
}
meaning.setText(ss);
}else {
meaning.setText(temp.getMeaning().substring(1));
}
return row;
}
我能够从列表中的特定行获取结果
对此但是点击功能不起作用,如果有人能告诉我我犯了什么错误,我将不胜感激
问候
在return
之前添加
meaning.setMovementMethod(LinkMovementMethod.getInstance());
此方法在 link 上启用了可点击功能。
在 ListView
中的一行上使用 Button 并且能够使单行 Spannable 和来自数据库的数据但是当我点击它时它没有响应点击这里是我的代码来自 MyAdapter Class
我在哪里输入数据库中的值到 Listview
public View getView(int i, View view, ViewGroup viewGroup) {
Realm realm=Realm.getDefaultInstance();
Word toEdit = realm.where(Word.class)
.equalTo("id", 10).findFirst();
int id_to_seperate=toEdit.getLang();
LayoutInflater inflater= (LayoutInflater) Main.context.getSystemService(Main.context.LAYOUT_INFLATER_SERVICE);
View row= inflater.inflate(R.layout.layout,viewGroup,false);
TextView word= (TextView) row.findViewById(R.id.word_name);
TextView meaning= (TextView) row.findViewById(R.id.word_define);
Word temp=list.get(i);
int idz=temp.getId();
word.setText(temp.getWord());
if(id_to_seperate==idz){
String span[] = temp.getMeaning().substring(1).split(" ") ;
SpannableString ss = new SpannableString(temp.getMeaning().substring(1));
ClickableSpan spans[] = new ClickableSpan[span.length];
for(int spanCount = 0 ; spanCount < span.length ; spanCount++){
spans[spanCount] = new ClickableSpan() {
@Override
public void onClick(View textView) {
TextView v = (TextView)textView ;
String text = v.getText().toString() ;
Log.d("View" , text);
}
};
}
int start = 0 ;
int end =0;
try {
for(int spanCount = 0 ; spanCount <span.length ; spanCount++){
if(spanCount==0) {
end += span[spanCount].length();
}else{
end += span[spanCount].length()+1;
}
ss.setSpan(spans[spanCount], start, end , Spanned.SPAN_EXCLUSIVE_EXCLUSIVE);
start += span[spanCount].length()+1;
}
} catch (Exception e) {
e.printStackTrace();
}
meaning.setText(ss);
}else {
meaning.setText(temp.getMeaning().substring(1));
}
return row;
}
我能够从列表中的特定行获取结果
对此
问候
在return
之前添加
meaning.setMovementMethod(LinkMovementMethod.getInstance());
此方法在 link 上启用了可点击功能。