完善转发模板功能

Perfect forwarding a template function

我正在尝试实现一个通用函数,该函数记录另一个函数花费多长时间 运行。

#include <iostream>
#include <future>
#include <thread>
#include <vector>
#include <functional>
#include <numeric>
#include <memory>

template<typename Res, typename Func, typename...Args>
std::pair<Res, double> ftime(Func fun, Args&&... args)
{
  auto start = std::chrono::system_clock::now();
  Res res = fun(std::forward<Args>(args)...);
  std::chrono::duration<double> duration = std::chrono::system_clock::now() - start;
  return std::make_pair(res, duration.count());
}

int main ()
{
  std::vector<int> values (100, 1);

  auto res = ftime(std::accumulate, values.begin(), values.end(), 0);
  std::cout << "Sum up " << values.size() << std::endl;
  std::cout << "Serial sum =  " <<  res.first << " took :  " << res.second << std::endl;
}

以上代码编译失败,出现以下错误:

sum_1000000.cpp: In function ‘int main()’:
sum_1000000.cpp:22:68: error: no matching function for call to ‘ftime(<unresolved overloaded function type>, std::vector<int>::iterator, std::vector<int>::iterator, int)’
   auto res = ftime(std::accumulate, values.begin(), values.end(), 0);
                                                                    ^
sum_1000000.cpp:10:24: note: candidate: template<class Res, class Func, class ... Args> std::pair<Res, double> ftime(Func, Args&& ...)
 std::pair<Res, double> ftime(Func fun, Args&&... args)
                        ^
sum_1000000.cpp:10:24: note:   template argument deduction/substitution failed:
sum_1000000.cpp:22:68: note:   couldn't deduce template parameter ‘Res’
   auto res = ftime(std::accumulate, values.begin(), values.end(), 0);

据我所知,编译器无法识别 std::acumulate 函数的模板类型。我做错了什么?

谢谢

代码中有几个问题。

推导函数return 先输入:

template<typename Func, typename...Args>
auto ftime(Func fun, Args&&... args) -> std::pair<decltype(fun(std::forward<Args>(args)...)), double>
{
  auto start = std::chrono::system_clock::now();
  auto res = fun(std::forward<Args>(args)...);
  std::chrono::duration<double> duration = std::chrono::system_clock::now() - start;
  return std::make_pair(res, duration.count());
}

std::accumulate 不是一个函数,而是一个模板。最简单的方法是将调用包装到 lambda 中:

auto res = ftime([&values]() { return std::accumulate(values.begin(), values.end(), 0); });

编译器无法推断出您模板的 Res,也无法推断出 accumulate.

的模板参数
#include <utility>
#include <chrono>
#include <vector>
#include <numeric>
#include <iostream>

template<typename Func, typename...Args>
auto invoke_timed(Func&& fun, Args&&... args) -> 
  std::pair<decltype(std::forward<Func>(fun)(std::forward<Args>(args)...)), 
  std::chrono::system_clock::duration::rep>
{
  auto start = std::chrono::system_clock::now();
  auto res = std::forward<Func>(fun)(std::forward<Args>(args)...);
  return std::make_pair(res, (std::chrono::system_clock::now() - start).count());
}

int main()
{
  std::vector<int> values(100, 1);
  auto res = invoke_timed(std::accumulate<std::vector<int>::iterator, int>, 
    values.begin(), values.end(), 0);

  std::cout << res.first << ", " << res.second << "\n";
  return 0;
}