如何使用 EasyRdf 获取 SPARQL 查询结果

How to fetch SPARQL query result using EasyRdf

使用EasyRdf,我想获取查询结果。我在 codeigniter 中使用了以下代码:

$this->load->library('rdf');
EasyRdf_Namespace::set('rdf', 'http://www.w3.org/1999/02/22-rdf-syntax-ns');
EasyRdf_Namespace::set('srt', 'http://persuratan-semweb.dev/ontologies/surat.owl');
$sparql = new EasyRdf_Sparql_Client('http://localhost:3030/surat_single/sparql');

$query = "SELECT * WHERE { "
            . "?surat rdf:type srt:Surat . "
            . "?surat srt:sifat_surat ?sifat_surat . "
            . "?surat srt:nomor_surat ?nomor_surat . }";
$result = $sparql->query($query);

echo "jumlah data: " . $result->numRows() . "<br>";
echo "<br>";

foreach ($result as $row) {
    echo $row->sifat_surat . " " .$row->sifat_surat . " " . $row->nomor_surat ."<br>";
}

print_r($result);

我得到的输出是:

jumlah data: 0

EasyRdf_Sparql_Result Object ( 
    [type:EasyRdf_Sparql_Result:private] => bindings
    [boolean:EasyRdf_Sparql_Result:private] =>
    [ordered:EasyRdf_Sparql_Result:private] =>
    [distinct:EasyRdf_Sparql_Result:private] =>
    [fields:EasyRdf_Sparql_Result:private] => Array ( 
        [0] => surat
        [1] => sifat_surat 
        [2] => nomor_surat 
    ) 
    [storage:ArrayIterator:private] => Array ( )
)

我也尝试了 Joshua 给出的解决方案 here, but got similar output. I also try my query in Fuseki endpoint (I'm using Fuseki triplestore) and got this result。我完全是语义网的初学者。

我不知道这是否是答案,但这些名称空间对我来说不合适:

EasyRdf_Namespace::set('rdf', 'http://www.w3.org/1999/02/22-rdf-syntax-ns');
EasyRdf_Namespace::set('srt', 'http://persuratan-semweb.dev/ontologies/surat.owl');

rdf 命名空间的末尾应该有一个 #,您的 OWL 文件也应该有一个:

EasyRdf_Namespace::set('rdf', 'http://www.w3.org/1999/02/22-rdf-syntax-ns#');
EasyRdf_Namespace::set('srt', 'http://persuratan-semweb.dev/ontologies/surat.owl#');

不过话虽如此,您没有理由不先尝试 更简单 查询。为什么不只是 运行

SELECT ?s ?p ?o { ?s ?p ?o }

确保你能得到结果,数据是什么。