联系人应用程序未按意图找到联系人

Contact Not Found on Intent with Contact Application

我想要的是当我按下列表中的项目时转到 Contact 应用程序中联系人的个人资料:

viewHolder.swipeLayout.setOnLongClickListener(new SwipeLayout.LongClickListener() {

        public void onLongPress(View view) {

            Intent goContactIntent = new Intent(Intent.ACTION_VIEW);
            String contactID = mData.get(position).getId();
            Uri uri = Uri.withAppendedPath(ContactsContract.Contacts.CONTENT_URI, contactID);
            Toast.makeText(mContext,"uri : "+uri, Toast.LENGTH_LONG).show();
            goContactIntent.setData(uri);
            view.getContext().startActivity(goContactIntent);
        }
    });

我在应用程序启动时使用 getContacts() 检索所有联系人的列表(姓名、phone 号码和 ID)。至少名字和 phone 数字有效。

public  ArrayList<Contact> getContacts() {
    //Adress of the table in the database
    Uri uri = ContactsContract.CommonDataKinds.Phone.CONTENT_URI;

    //Retrieve data
    String[] projection    = new String[] {ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME,
            ContactsContract.CommonDataKinds.Phone.NUMBER, ContactsContract.CommonDataKinds.Phone._ID};

    //Initialize the cursor
    Cursor people = getContentResolver().query(uri, projection, null, null, null);

    int indexName = people.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
    int indexNumber = people.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
    int indexId = people.getColumnIndex(ContactsContract.CommonDataKinds.Phone._ID);

    ArrayList<Contact> contacts = new ArrayList<Contact>();

    //Shaping data
    people.moveToFirst();
    do {
        String name   = people.getString(indexName);
        String number = people.getString(indexNumber);
        String contactid = people.getString(indexId);

        Contact contact1 = new Contact();

        contact1.setFirstName(name);
        contact1.setPhoneNumber(number);
        contact1.setId(contactid);

        contacts.add(contact1);

    } while (people.moveToNext());

    return contacts;
}

onLongPress 函数中,当我敬酒时,我得到如下 URI:"content://com.android.contacts/contacts/780" 祝酒词(我没有实现):"Contact not found"

我知道如何访问 Contact 应用程序(我有适用的代码),但我无法访问特定的联系人资料。

我认为你在 URI 中传递的 ID 是错误的。我正在使用 ContactsContract.RawContacts.CONTACT_ID,它工作得很好