ReactFX

Question

这里是响应式编程的新手。

我正在尝试使用 ReactFX 在 JavaFX 中实现 "lazy" 实时搜索文本区域。这里的懒惰是指一旦用户停止输入一秒钟，它就会执行搜索。代码非常简单：

EventStream<Change<String>> textEvents = EventStreams.changesOf(textArea.textProperty())
.successionEnds(Duration.ofSeconds(1));

然后订阅该事件流，瞧瞧。

但我还希望它在用户按下 Enter 时立即执行搜索。我不确定如何以 "reactive" 的方式做到这一点。简单地对 Enter 键事件执行搜索会导致搜索触发两次（一次用于键事件，一次用于文本更改），所以这是我当前的解决方案：

BooleanProperty hasSearched = new SimpleBooleanProperty(false);
EventStream<KeyEvent> enterKeyPressedEvents = EventStreams.eventsOf(textArea, KeyEvent.KEY_PRESSED)
        .filter(k -> k.getCode() == KeyCode.ENTER);
AwaitingEventStream<Change<String>> textEvents = EventStreams.changesOf(textArea.textProperty())
        .successionEnds(Duration.ofSeconds(1));

subs = Subscription.multi(
        //Text changed
        textEvents.subscribe(e -> {
            if (hasSearched.get()) {
                hasSearched.set(false);
                System.out.println("ignored text event");
            } else {
                performSearch(textArea.getText());
            }
        }),

        //Enter key pressed
        enterKeyPressedEvents.subscribe(e -> {
            e.consume();
            if (e.isShiftDown()) {
                textArea.insertText(textArea.getCaretPosition(), "\n");
            } else {
                hasSearched.set(true);
                System.out.println("enter pressed");
                performSearch(textArea.getText());
                if (!textEvents.isPending()) {
                    hasSearched.set(false);
                }
            }
        })
);

我试过使用 SuspendableEventStream.suspend() 认为它会 "drop" 所有未决事件，但它没有按预期工作，仍会发出未决事件：

EventStream<KeyEvent> enterKeyPressedEvents = EventStreams.eventsOf(textArea, KeyEvent.KEY_PRESSED)
        .filter(k -> k.getCode() == KeyCode.ENTER);
SuspendableEventStream<Change<String>> textEvents = EventStreams.changesOf(textArea.textProperty())
        .successionEnds(Duration.ofSeconds(1)).suppressible();

subs = Subscription.multi(
        //Text changed
        textEvents.subscribe(e -> {
                performSearch(textArea.getText());
        }),

        //Enter key pressed
        enterKeyPressedEvents.subscribe(e -> {
            e.consume();
            if (e.isShiftDown()) {
                textArea.insertText(textArea.getCaretPosition(), "\n");
            } else {
                Guard guard = textEvents.suspend();
                System.out.println("enter pressed");
                performSearch(textArea.getText());
                guard.close();
            }
        })
);

我怎样才能想到更好（更具反应性？）的解决方案？

Answer 1

未测试，但怎么样：

EventStream<KeyEvent> enterKeyPressedEvents = EventStreams.eventsOf(textArea, KeyEvent.KEY_PRESSED)
        .filter(k -> k.getCode() == KeyCode.ENTER);
EventStream<Change<String>> textEvents = EventStreams.changesOf(textArea.textProperty())
        .successionEnds(Duration.ofSeconds(1))
        .filter(c -> ! isAdditionOfNewline(c, textArea.getCaratPosition()));

EventStreams.merge(enterKeyPressedEvents, textEvents)
        .subscribe(o -> performSearch(textArea.getText()));

private boolean isAdditionOfNewline(Change<String> change, int caratPos) {
    // TODO make sure this works as required
    String oldText = change.getOldValue();
    String newText = change.getNewValue();
    if (oldText.length()+1 != newText.length() || caratPos == 0) {
        return false ;
    }

    return oldText.equals(newText.substring(0, caratPos-1) + newText.substring(caratPos));
}

Answer 2

这是一个解决方案。此解决方案的关键部分是观察 flatMap 内的文本变化，它具有 "resetting" 文本流变化的效果。

import java.time.Duration;
import java.util.function.Function;

import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.control.TextArea;
import javafx.scene.input.KeyCode;
import javafx.scene.input.KeyEvent;
import javafx.stage.Stage;

import org.reactfx.EventStream;
import org.reactfx.EventStreams;

public class AutoSearch extends Application {

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage stage) throws Exception {
        TextArea area = new TextArea();

        EventStream<KeyEvent> enterPresses = EventStreams.eventsOf(area, KeyEvent.KEY_PRESSED)
                .filter(k -> k.getCode() == KeyCode.ENTER)
                .hook(KeyEvent::consume);

        EventStream<?> searchImpulse = enterPresses.withDefaultEvent(null) // emit an event even before Enter is pressed
                .flatMap(x -> {
                    EventStream<?> edits = EventStreams.changesOf(area.textProperty())
                                                       .successionEnds(Duration.ofSeconds(1));
                    return ((x == null) ? edits : edits.withDefaultEvent(null))
                            .map(Function.identity()); // just to get the proper type of the result
                });

        searchImpulse.subscribe(x -> System.out.println("Search now!"));

        stage.setScene(new Scene(area));
        stage.show();
    }

}

Answer 3

这是另一种解决方案。这个计算 Enter 按下次数，并且仅当 Enter 计数在此期间未更改时才让编辑事件触发搜索。

import java.time.Duration;

import javafx.application.Application;
import javafx.scene.Scene;
import javafx.scene.control.TextArea;
import javafx.scene.input.KeyCode;
import javafx.scene.input.KeyEvent;
import javafx.stage.Stage;

import org.reactfx.EventStream;
import org.reactfx.EventStreams;

public class AutoSearch2 extends Application {

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage stage) throws Exception {
        TextArea area = new TextArea();

        EventStream<KeyEvent> enterPressed = EventStreams.eventsOf(area, KeyEvent.KEY_PRESSED)
                .filter(k -> k.getCode() == KeyCode.ENTER)
                .hook(KeyEvent::consume);

        EventStream<Long> enterCount = enterPressed.accumulate(0L, (n, k) -> n + 1)
                                                   .withDefaultEvent(0L);

        EventStream<Long> delayedEdits = enterCount.emitOnEach(EventStreams.changesOf(area.textProperty()))
                                                   .successionEnds(Duration.ofSeconds(1));

        // check that the delayed edit event still has the current value of the Enter counter
        EventStream<?> validEdits = enterCount.emitBothOnEach(delayedEdits)
                                              .filter(cd -> cd.test((current, delayed) -> delayed == current));

        EventStream<?> searchImpulse = EventStreams.merge(enterPressed, validEdits);

        searchImpulse.subscribe(x -> System.out.println("Search now!"));

        stage.setScene(new Scene(area));
        stage.show();
    }

}

ReactFX - "lazy" 实时搜索文本区域

ReactFX - "lazy" real-time search text area

java

javafx

javafx-8

reactive-programming