onActivityResult 在 setResult 之后没有被调用

onActivityResult not being called after setResult

我有一个 activity A - 它在 Viewpager 中包含 3 个片段。片段号 1,是新闻文章列表,当用户从列表中选择新闻文章时,activityB 启动并显示所选文章的详细信息(标题,body,评论)。我希望用户能够通过使用选项菜单选择 activity A 他想要 return 的哪个片段。

Activity答:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {

    switch (resultCode) {
    case 0:
        mPager.setCurrentItem(0);
        break;
    case 1:
        mPager.setCurrentItem(1);
        break;
    case 2:
        mPager.setCurrentItem(2);
        break;
    }
}

Activity乙:

@Override
public boolean onOptionsItemSelected(MenuItem item) {
    Intent intent = new Intent(this, MainActivity.class);
    switch (item.getItemId()) {
        case R.id.menu_noticias:
            //startActivityForResult(intent, 0);
            setResult(0, intent);
            finish();
            return true;
        case R.id.menu_contactos:
            //startActivityForResult(intent, 1);
            setResult(1, intent);
            finish();
            return true;
        case R.id.menu_cumples:
            //startActivityForResult(intent, 2);
            setResult(2, intent);
            finish();
            return true;
        default:
            return super.onOptionsItemSelected(item);
    }
}

你不应该从 activity B 调用 startActivityForResult。从 A 开始,你通过调用 startActivityForResult 然后从 B 开始 activity B足以设置结果并完成 activity

Activity答:

Intent intent = new Intent();
...
startActivityForResult(intent, 0);

Activity乙:

case R.id.menu_noticias:
    intent.putExtra("menu", 0);
    setResult(RESULT_OK, intent);
    finish();
    return true;

然后 activity 答:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (resultCode == RESULT_OK) {
        int menu = data.getExtraInt("menu");
        switch (menu) {
        case 0:
            mPager.setCurrentItem(0);
            break;
        }
    }
}