awk 操作多个文件

Question

我有以下文件 file1 和 file2（例如）

$cat file1.txt
SERVICE: 1
TASK: 1
RESULT: 1
ADDITIONAL: 1

SERVICE: 2
TASK: 2
RESULT: 2
ADDITIONAL: 2

SERVICE: 3
TASK: 3
RESULT: 3
ADDITIONAL: 3

$cat file2.txt
SERVICE: 1
TASK: 1
RESULT: 1
ADDITIONAL: 1

SERVICE: 2
TASK: 2
RESULT: 2
ADDITIONAL: 2

SERVICE: 3
TASK: 3
RESULT: 3
ADDITIONAL: 3

我需要以下输出：

文件名和服务上循环的每个块：在下面的 1 行中，用竖线“|”分隔“

file1.txt | SERVICE: 1 | TASK: 1 | RESULT: 1 | ADDITIONAL: 1
file1.txt | SERVICE: 2 | TASK: 2 | RESULT: 2 | ADDITIONAL: 2
file1.txt | SERVICE: 3 | TASK: 3 | RESULT: 3 | ADDITIONAL: 3

file2.txt | SERVICE: 1 | TASK: 1 | RESULT: 1 | ADDITIONAL: 1
file2.txt | SERVICE: 2 | TASK: 2 | RESULT: 2 | ADDITIONAL: 2
file2.txt | SERVICE: 3 | TASK: 3 | RESULT: 3 | ADDITIONAL: 3

你能帮我想办法实现这个吗

到目前为止，我能够将它排成一行，但我无法在服务上循环的每个块前面获取文件名：

我的命令如下：

cat * | awk -F ":" '/^SERVICE:/ {print ""} {printf"|" substr([=13=], index([=13=],))}'

非常感谢您的帮助

Answer 1

$ awk -v RS= -F'\n' -v OFS=' | ' '{ = FILENAME OFS }1' file1.txt file2.txt
file1.txt | SERVICE: 1 | TASK: 1 | RESULT: 1 | ADDITIONAL: 1
file1.txt | SERVICE: 2 | TASK: 2 | RESULT: 2 | ADDITIONAL: 2
file1.txt | SERVICE: 3 | TASK: 3 | RESULT: 3 | ADDITIONAL: 3
file2.txt | SERVICE: 1 | TASK: 1 | RESULT: 1 | ADDITIONAL: 1
file2.txt | SERVICE: 2 | TASK: 2 | RESULT: 2 | ADDITIONAL: 2
file2.txt | SERVICE: 3 | TASK: 3 | RESULT: 3 | ADDITIONAL: 3

awk 操作多个文件

awk to manipulate multiple files

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