如何在 jwt-auth 中获取授权用户的 ID?
How to get ID of authorized user in jwt-auth?
如何获取jwt-auth中授权用户的ID?
我尝试通过标准方法获取 id,但它不起作用
使用jwt-auth时,您可以通过解析 JWT 令牌获取用户 ID:
public function getAuthenticatedUser()
{
try {
if (! $user = JWTAuth::parseToken()->authenticate()) {
return response()->json(['user_not_found'], 404);
}
} catch (Tymon\JWTAuth\Exceptions\TokenExpiredException $e) {
return response()->json(['token_expired'], $e->getStatusCode());
} catch (Tymon\JWTAuth\Exceptions\TokenInvalidException $e) {
return response()->json(['token_invalid'], $e->getStatusCode());
} catch (Tymon\JWTAuth\Exceptions\JWTException $e) {
return response()->json(['token_absent'], $e->getStatusCode());
}
$userId = $user->id;
# code...
}
如何获取jwt-auth中授权用户的ID? 我尝试通过标准方法获取 id,但它不起作用
使用jwt-auth时,您可以通过解析 JWT 令牌获取用户 ID:
public function getAuthenticatedUser()
{
try {
if (! $user = JWTAuth::parseToken()->authenticate()) {
return response()->json(['user_not_found'], 404);
}
} catch (Tymon\JWTAuth\Exceptions\TokenExpiredException $e) {
return response()->json(['token_expired'], $e->getStatusCode());
} catch (Tymon\JWTAuth\Exceptions\TokenInvalidException $e) {
return response()->json(['token_invalid'], $e->getStatusCode());
} catch (Tymon\JWTAuth\Exceptions\JWTException $e) {
return response()->json(['token_absent'], $e->getStatusCode());
}
$userId = $user->id;
# code...
}