将 3D numpy 数组拆分为 3D 块

Question

我想以 'pythonic' 的方式将 3D numpy 数组拆分为 3D 块。我处理的图像序列有些大（1000X1200X1600），所以我需要将它们分成几块来进行处理。

我已经编写了函数来执行此操作，但我想知道是否有原生的 numpy 方法来完成此操作 - numpy.split 似乎无法满足我对 3D 数组的要求（但也许我没有不了解其功能）

明确一点：下面的代码完成了我的任务，但我正在寻找一种更快的方法来完成它。

def make_blocks(x,t):
#x should be a yXmXn matrix, and t should even divides m,n
#returns a list of 3D blocks of size yXtXt 
    down =  range(0,x.shape[1],t)
    across = range(0,x.shape[2],t)
    reshaped = []
    for d in down:
        for a in across:
            reshaped.append(x[:,d:d+t,a:a+t])
    return reshaped

def unmake_blocks(x,d,m,n):
#this takes a list of matrix blocks of size dXd that is m*n/d^2 long 
#returns a 2D array of size mXn
    rows = []
    for i in range(0,int(m/d)):
        rows.append(np.hstack(x[i*int(n/d):(i+1)*int(n/d)]))
    return np.vstack(rows)

Answer 1

这里是那些循环实现的矢量化版本，使用置换 dims 与 np.transpose and reshaping -

的组合

def make_blocks_vectorized(x,d):
    p,m,n = x.shape
    return x.reshape(-1,m//d,d,n//d,d).transpose(1,3,0,2,4).reshape(-1,p,d,d)

def unmake_blocks_vectorized(x,d,m,n):    
    return np.concatenate(x).reshape(m//d,n//d,d,d).transpose(0,2,1,3).reshape(m,n)

样本运行 make_blocks -

In [120]: x = np.random.randint(0,9,(2,4,4))

In [121]: make_blocks(x,2)
Out[121]: 
[array([[[4, 7],
         [8, 3]],

        [[0, 5],
         [3, 2]]]), array([[[5, 7],
         [4, 0]],

        [[7, 3],
         [5, 7]]]), ... and so on.

In [122]: make_blocks_vectorized(x,2)
Out[122]: 
array([[[[4, 7],
         [8, 3]],

        [[0, 5],
         [3, 2]]],


       [[[5, 7],
         [4, 0]],

        [[7, 3],
         [5, 7]]],  ... and so on.

样本运行 unmake_blocks -

In [135]: A = [np.random.randint(0,9,(3,3)) for i in range(6)]

In [136]: d = 3

In [137]: m,n = 6,9

In [138]: unmake_blocks(A,d,m,n)
Out[138]: 
array([[6, 6, 7, 8, 6, 4, 5, 4, 8],
       [8, 8, 3, 2, 7, 6, 8, 5, 1],
       [5, 2, 2, 7, 1, 2, 3, 1, 5],
       [6, 7, 8, 2, 2, 1, 6, 8, 4],
       [8, 3, 0, 4, 4, 8, 8, 6, 3],
       [5, 5, 4, 8, 5, 2, 2, 2, 3]])

In [139]: unmake_blocks_vectorized(A,d,m,n)
Out[139]: 
array([[6, 6, 7, 8, 6, 4, 5, 4, 8],
       [8, 8, 3, 2, 7, 6, 8, 5, 1],
       [5, 2, 2, 7, 1, 2, 3, 1, 5],
       [6, 7, 8, 2, 2, 1, 6, 8, 4],
       [8, 3, 0, 4, 4, 8, 8, 6, 3],
       [5, 5, 4, 8, 5, 2, 2, 2, 3]])

替代 make_blocks 与 view_as_blocks -

from skimage.util.shape import view_as_blocks

def make_blocks_vectorized_v2(x,d):
    return view_as_blocks(x,(x.shape[0],d,d))

运行时测试

1) make_blocks 使用原始和基于 view_as_blocks 的方法 -

In [213]: x = np.random.randint(0,9,(100,160,120)) # scaled down by 10

In [214]: %timeit make_blocks(x,10)
1000 loops, best of 3: 198 µs per loop

In [215]: %timeit view_as_blocks(x,(x.shape[0],10,10))
10000 loops, best of 3: 85.4 µs per loop

2) unmake_blocks 原始和基于 transpose+reshape 的方法 -

In [237]: A = [np.random.randint(0,9,(10,10)) for i in range(600)]

In [238]: d = 10

In [239]: m,n = 10*20,10*30

In [240]: %timeit unmake_blocks(A,d,m,n)
100 loops, best of 3: 2.03 ms per loop

In [241]: %timeit unmake_blocks_vectorized(A,d,m,n)
1000 loops, best of 3: 511 µs per loop

将 3D numpy 数组拆分为 3D 块

Split a 3D numpy array into 3D blocks

performance

numpy

memory-efficient

python-2.7