隐式参数值本身就是隐式值吗？

Question

换句话说，函数的隐式参数是函数范围内的隐式值吗？

这里有一个小测试：

object ImplicitTest{

  case class Foo()

  def myOtherFun()(implicit myfoo: Foo) = {
    val grabImpFoo = implicitly[Foo]
    println(myfoo.toString + " from myOtherFun")
  }
}

import ImplicitTest._

class ImplicitTest {
  def myFun()(implicit myfoo: Foo) = {
    println(myfoo.toString)
    myOtherFun()
  }

}

现在运行它：

  implicit val foo = Foo()
  val it = new ImplicitTest()
  it.myFun()

这似乎向我证明了隐式参数本身是隐式的，因为 myOtherFun 可以找到一个隐式参数，有一段时间我不相信是这样！我想这有利有弊，但我只是来这里了解事实；我查看了 http://docs.scala-lang.org/tutorials/FAQ/finding-implicits.html (based on Passing scala.math.Integral as implicit parameter) 并且没有看到任何提及这个事实，如果我理解正确的话。

Answer 1

Years 隐式参数可以被范围内具有匹配隐式类型的其他函数访问

取自http://docs.scala-lang.org/tutorials/tour/implicit-parameters.html

The actual arguments that are eligible to be passed to an implicit parameter fall into two categories:

First, eligible are all identifiers x that can be accessed at the point of the method call without a prefix and that denote an implicit definition or an implicit parameter.

Second, eligible are also all members of companion modules of the implicit parameter’s type that are labeled implicit.

隐式参数值本身就是隐式值吗？

Are implicit parameter values implicit values themselves?

scala

implicit