Java 抛出一个我认为不应该抛出的异常

Question

System.out.println("\nHow many sticks do you want?");
    while(sticks==0){
        try{
            sticks=startInput.nextInt();
        }catch(InputMismatchException e){
            sticks=0;
            System.out.println("Please enter a valid number.");
        }
        sticks=startInput.nextInt();
    }

我尝试做的事情：它要求输入一个 int，但是当有人输入 chars 时，它应该再次询问而不是崩溃。

Answer 1

第二个 sticks=startInput.nextInt(); 不在 try-catch 块内，因此如果您放置更多字符，它将再次失败。由于您没有自己处理异常，异常会冒泡并最终使您的应用程序崩溃。

编辑：根据您的评论，视情况而定。假设您想关闭您的应用程序 when/should 用户提供 0 作为您问题的答案，您可以这样做：

System.out.println("\nHow many sticks do you want?");
    while(sticks >= 0){
        try{
            sticks=startInput.nextInt();
        }catch(InputMismatchException e){
            sticks=0;     //Any value which is not 0 will not break your loop. This will be re-populated when the user will supply the number again.
            System.out.println("Please enter a valid number.");
        }
    }

如果您希望您的应用程序从您的代码中停止（这似乎不太可能）：

System.out.println("\nHow many sticks do you want?");
    while(sticks==0){
        try{
            sticks=startInput.nextInt();
        }catch(InputMismatchException e){
            sticks=0;     //The 0 will break your while loop, exiting your application gracefully.
            System.out.println("Please enter a valid number.");
        }
    }

这是有效的方法：

private static int sticks;
    private static Scanner startInput;

    public static void main(String[] args) {
        sticks = 0;
        startInput = new Scanner(System.in);        
        while (sticks >= 0) {            
            try {
                System.out.println("How many sticks do you want?");
                sticks = Integer.parseInt(startInput.nextLine());
            } catch (NumberFormatException e) {
                sticks = 0;     //Any value which is not 0 will not break your loop. This will be re-populated when the user will supply the number again.
                System.out.println("Please enter a valid number.");
            }
        }
    }

Answer 2

似乎你没有在这里放一个循环，检查下面的代码:

while(true){
    System.out.println("\nHow many sticks do you want?");
        while(sticks==0){
            try{
                sticks=startInput.nextInt();
            }catch(InputMismatchException e){
                sticks=0;
                System.out.println("Please enter a valid number.");
            }
        }
    }

Java 抛出一个我认为不应该抛出的异常

Java throws out an exception where I think it shouldnt

java

exception

crash

try-catch