SendInput 显示乱序发送的数据

SendInput showing data sent out of sequence

我正在通过向备忘录发送字符串来试验 SendInput。我将 SendInput 命令与对 Memo.Lines.Add('....') 的调用混合使用。令我惊讶的是,所有 Memo.Lines.Add 命令都在任何 SendInput 例程之前执行。为什么?如何让备忘录以正确的顺序显示信息?

我的代码如下所示:

procedure TForm1.Button1Click(Sender: TObject);
const
  AStr = '123 !@# 890 *() abc ABC';
var
  i: integer;
  KeyInputs: array of TInput;

  procedure KeybdInput(VKey: Byte; Flags: DWORD);
  begin
    SetLength(KeyInputs, Length(KeyInputs)+1);
    KeyInputs[high(KeyInputs)].Itype := INPUT_KEYBOARD;
    with  KeyInputs[high(KeyInputs)].ki do
    begin
      wVk := VKey;
      wScan := MapVirtualKey(wVk, 0);
      dwFlags := Flags;
    end;
  end;

begin
  Memo1.SetFocus;
  Memo1.Lines.Add('AStr := ' + AStr);

  Memo1.Lines.Add('');
  Memo1.Lines.Add('Use:   KeybdInput(ord(AStr[i]),0)');
  SetLength(KeyInputs,0);
  for i := 1 to Length(AStr) do KeybdInput(ord(AStr[i]),0);
  SendInput(Length(KeyInputs), KeyInputs[0], SizeOf(KeyInputs[0]));

  Memo1.Lines.Add('');
  Memo1.Lines.Add('Use:   KeybdInput(vkKeyScan(AStr[i]),0)');
  SetLength(KeyInputs,0);
  for i := 1 to Length(AStr) do KeybdInput(vkKeyScan(AStr[i]),0);
  SendInput(Length(KeyInputs), KeyInputs[0], SizeOf(KeyInputs[0]));
end;

我希望结果是这样的:

但实际上是这样的:

您使用 SendInput 发送的键盘输入通过 Windows 消息系统并最终进入您的应用程序消息队列。在您退出 Button1Click().

之前,消息队列未被处理

When something gets added to a queue, it takes time for it to come out the front of the queue

要按您期望的顺序查看事件,您需要在每个 SendInput() 之后插入对 Application.Processmessages() 的调用。尽管通常不建议调用 Application.ProcessMessages()

The Dark Side of Application.ProcessMessages in Delphi Applications