在 python 中仅拟合具有多个参数的函数的 2 个参数

Question

我知道有一个问题
Fitting only one parameter of a function with many parameters in python
但我的情况有点不同。 lambda 函数的参数问题。

我正在尝试拟合洛伦兹函数

def lorentz(ph, A, xc, w, f0):
    return f0 + A * w**2 / (w**2 + (ph - xc)**2)

如果我只拟合一个参数 (xc)，它工作正常。

p1, p2, p3, p4 = params
popt, pcov = curve_fit(lambda x, xc: lorentz(x, p1, xc, p3, p4), abjd, adata, bounds=param_bounds)

但是如果我尝试只拟合 2 个参数 (a, xc)，它会失败

p1, p2, p3, p4 = params    
popt, pcov = curve_fit(lambda x, a, xc: lorentz(x, a, xc, p3, p4), abjd, adata, bounds=param_bounds)

错误信息是

Traceback (most recent call last):
  File "template.py", line 294, in <module>
    popt, pcov = curve_fit(lambda x, a, xc: lorentz(x, a, xc, p3, p4), abjd, adata, bounds=param_bounds)
  File "/usr/local/lib/python2.7/dist-packages/scipy/optimize/minpack.py", line 683, in curve_fit
    **kwargs)
  File "/usr/local/lib/python2.7/dist-packages/scipy/optimize/_lsq/least_squares.py", line 769, in least_squares
    f0 = fun_wrapped(x0)
  File "/usr/local/lib/python2.7/dist-packages/scipy/optimize/_lsq/least_squares.py", line 764, in fun_wrapped
    return np.atleast_1d(fun(x, *args, **kwargs))
  File "/usr/local/lib/python2.7/dist-packages/scipy/optimize/minpack.py", line 455, in func_wrapped
    return func(xdata, *params) - ydata
TypeError: <lambda>() takes exactly 3 arguments (2 given)

Answer 1

这是洛伦兹函数所有 4 个参数的解

import numpy as np
from scipy.optimize import curve_fit

def lorentz(ph, A, xc, w, f0):
    return f0 + A * w**2 / (w**2 + (ph - xc)**2)

A, xc, w, f0 = 2,2,2,2  # true values
ph = np.linspace(-5, 10, 100)
y = lorentz(ph, A, xc, w, f0)    
ydata = y + 0.15 * np.random.normal(size=len(ph)) # sample data
popt, pcov = curve_fit(lambda x, _A, _xc: lorentz(x, _A, _xc, w, f0), ph, ydata,bounds=([1,1], [3, 3]))
A, xc = popt # fitted values (only two)

您可以轻松地添加或删除参数，只需将它们放在函数 lorentz() 下或使用 lambda

结果是这样的

在 python 中仅拟合具有多个参数的函数的 2 个参数

Fitting only 2 paramter of a function with many parameters in python

python

lambda

scipy

curve-fitting