凯撒密码 Python 分行打印

Question

下面的代码工作正常，但是消息在加密后打印到不同的行。例如，如果我输入：abc，移位 1，它会对其进行加密，但会打印为：

b
c
d

我不明白为什么。我希望它打印为：

bcd

代码如下：

print("Welcome to the Code-Breaking/Making Software")
print("This program uses something called a Caesar Cipher.")

Message = (input("Please enter the message you wish to Encrypt >> "))
Shift = int(input("Please enter the shift for your message >> "))

for x in Message:
    OrdMessage = ord(x) 
    ShiftedMessage = OrdMessage + Shift
    NewMessage = chr(ShiftedMessage)
    NewMessageList = list(NewMessage)
    print("".join(NewMessageList))

Answer 1

缩进很重要，您不应该每次都创建 NewMessage 的新列表

print("Welcome to the Code-Breaking/Making Software")
print("This program uses something called a Caesar Cipher.")

Message = (input("Please enter the message you wish to Encrypt >> "))
Shift = int(input("Please enter the shift for your message >> "))

NewMessageList = []
for x in Message:
    OrdMessage = ord(x) 
    ShiftedMessage = OrdMessage + Shift
    NewMessage = chr(ShiftedMessage)
    NewMessageList.append(NewMessage)
print("".join(NewMessageList))

Answer 2

您应该更改以下部分；

print("".join(NewMessageList), end="")

Answer 3

发生的事情是，对于每个字符，它都是运行循环并打印答案，现在我收集了所有加密的字母，最后将它们合并为一个并打印出来。

它首先使用 NewMessage = [] 初始化一个空列表，然后对于我们加密的每个字母，它使用 .append() 添加到该空列表，最后通过 ''.join(NewMessage) 打印所有

print("Welcome to the Code-Breaking/Making Software")
print("This program uses something called a Caesar Cipher.")

Message = (input("Please enter the message you wish to Encrypt >> "))
Shift = int(input("Please enter the shift for your message >> "))

NewMessage = []
for x in Message:
    OrdMessage = ord(x) 
    ShiftedMessage = OrdMessage + Shift
    NewMessage.append(chr(ShiftedMessage)) 
print(''.join(NewMessage))

凯撒密码 Python 分行打印

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