如何在 C# 中为动态二维按钮数组创建单击事件处理程序

Question

我需要动态生成 2D "card" 按钮。我将如何着手给每个人一个事件处理程序并能够直接引用按钮？

public void generateButtonsCard(Panel cardPanel)
    {
        for (int y = 0; y <= 4; y++)
        {
            for (int x = 0; x <= 4; x++)
            {
                cardButtons[x, y] = new Button();
                cardButtons[x, y].Size = new Size(80, 80);
                cardButtons[x, y].Name = "btn" + x + "" + y;
                cardButtons[x, y].Location = new Point(80 * x, 80 * y);
                cardPanel.Controls.Add(cardButtons[x, y]);

            }

        }

        RNGCard();
        cardButtons[2, 2].Text = "Free Space";

    }

Answer 1

试试这个，

public void generateButtonsCard(Panel cardPanel)
{
    for (int y = 0; y <= 4; y++)
    {
        for (int x = 0; x <= 4; x++)
        {
            cardButtons[x, y] = new Button();
            cardButtons[x, y].Size = new Size(80, 80);
            cardButtons[x, y].Name = "btn" + x + "" + y;
            cardButtons[x, y].Location = new Point(80 * x, 80 * y);
            cardButtons[x, y].Click += btn_Click;
            cardPanel.Controls.Add(cardButtons[x, y]);

        }

    }

    RNGCard();
    cardButtons[2, 2].Text = "Free Space";

}

private void btn_Click(object sender, EventArgs e){   
        Button b = sender as Button;
        //if (b.Name == "1")
        //{
            label1.Text = b.Name.ToString();
        //}
}

结果；

在 Click 事件中，sender 代表按钮。您可以使用按钮的属性（如评论区域）检查您的随机变量。（在结果图像中没有 if 条件 btw。）

希望有所帮助，

Answer 2

因此您可以创建一个按钮单击事件处理程序，并且在该处理程序中您可以根据哪个按钮被单击来切换您的逻辑。以下是如何操作的示例：

public class XYButton : Button
{
    private int xPos;
    private int yPos;

    public XYButton(int x, int y)
    {
        xPos = x;
        yPos = y;
    }

    public int GetX()
    {
        return xPos;
    }

    public int GetY()
    {
        return yPos;
    }
}

然后使用这个新的按钮扩展...

public void generateButtonsCard(Panel cardPanel)
{
    for (int y = 0; y <= 4; y++)
    {
        for (int x = 0; x <= 4; x++)
        {
            cardButtons[x, y] = new XYButton(x,y);
            cardButtons[x, y].Size = new Size(80, 80);
            cardButtons[x, y].Name = "btn" + x + "" + y;
            cardButtons[x, y].Location = new Point(80 * x, 80 * y);
            cardButtons[x, y].Click += btn_Click;
            cardPanel.Controls.Add(cardButtons[x, y]);

        }

    }

    RNGCard();
    cardButtons[2, 2].Text = "Free Space";

}

private void btn_Click(object sender, EventArgs e){
   var xyButton = sender as XYButton;
   // now you can get the x and y position from xyButton.
}

Answer 3

如果您要动态创建按钮，那么您应该动态创建事件处理程序。创建 void btn_Click(object sender, EventArgs e) 违背了良好的 OO 设计 - 您想要封装代码而不是将其留在那里供任何代码调用。

方法如下：

public void generateButtonsCard(Panel cardPanel)
{
    for (int y = 0; y <= 4; y++)
    {
        for (int x = 0; x <= 4; x++)
        {
            var button = new Button();
            button.Size = new Size(80, 80);
            button.Name = "btn" + x + "" + y;
            button.Location = new Point(80 * x, 80 * y);
            button.Click += (s, e) =>
            {
                /* Your event handling code here
                   with full access to `button` above */
            };
            cardPanel.Controls.Add(button);
            cardButtons[x, y] = button;
        }
    }
    RNGCard();
    cardButtons[2, 2].Text = "Free Space";
}

处理程序封装在 generateButtonsCard 方法中，您可以完全访问处理程序中的 button 实例。干净整洁。

如何在 C# 中为动态二维按钮数组创建单击事件处理程序

How to create click event handler for a dynamic 2D array of buttons in C#

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