SQL 删除两个表之间的时间重叠

Question

我有两个 table。每个 table 有两个字段：from_date 和 to_date。我需要找到 table A 中不与 table B 中的记录重叠的所有记录。

我正在使用 MSSQL 2008。

CREATE TABLE Table_A(from_date datetime , to_date datetime )

CREATE TABLE Table_B(from_date datetime , to_date datetime )

Insert into Table_A (from_date, to_date) values ('2016-09-01 10:00:00','2016-09-01 11:00:00')

Insert into Table_A (from_date, to_date) values ('2016-09-01 11:00:00','2016-09-01 12:00:00')

Insert into Table_A (from_date, to_date) values ('2016-09-01 12:00:00','2016-09-01 13:00:00')

Insert into Table_B (from_date, to_date) values ('2016-09-01 10:00:00','2016-09-01 12:00:00')

Insert into Table_B (from_date, to_date) values ('2016-09-01 13:00:00','2016-09-01 14:00:00')

Insert into Table_B (from_date, to_date) values ('2016-09-01 14:00:00','2016-09-01 15:00:00')

结果应该只是TableA（1200-1300）中的第三条记录，因为它不与TableB中的任何记录重叠。

Answer 1

如果您不想重叠，可以采用以下一种方法：

select a.*
from table_a a
where not exists (select 1
                  from table_b b
                  where a.from_date < b.to_date and a.to_date > b.from_date
                 );

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