如何检查两个以上 URL 的 HTTP 错误？

Question

问题：我有 3 个 URL - testurl1、testurl2 和 testurl3。我想先尝试 testurl1，如果出现 404 错误，则尝试 testurl2，如果出现 404 错误，则尝试 testurl3。如何做到这一点？到目前为止，我已经在下面尝试过，但仅适用于两个 url，如何添加对第三个 url 的支持？

from urllib2 import Request, urlopen
from urllib2 import URLError, HTTPError

def checkfiles():
    req = Request('http://testurl1')
    try:
        response = urlopen(req)
        url1=('http://testurl1')

    except HTTPError, URLError:
        url1 = ('http://testurl2')

    print url1
    finalURL='wget '+url1+'/testfile.tgz'

    print finalURL

checkfiles()

Answer 1

普通旧 for 循环的另一项工作：

for url in testurl1, testurl2, testurl3
    req = Request(url)
    try:
        response = urlopen(req)
    except HttpError as err:
        if err.code == 404:
            continue
        raise
    else:
        # do what you want with successful response here (or outside the loop)
        break
else:
    # They ALL errored out with HTTPError code 404.  Handle this?
    raise err

Answer 2

嗯，也许是这样的？

from urllib2 import Request, urlopen
from urllib2 import URLError, HTTPError

def checkfiles():
    req = Request('http://testurl1')
    try:
        response = urlopen(req)
        url1=('http://testurl1')

    except HTTPError, URLError:
        try:
            url1 = ('http://testurl2')
        except HTTPError, URLError:
            url1 = ('http://testurl3')
    print url1
    finalURL='wget '+url1+'/testfile.tgz'

    print finalURL

checkfiles()

如何检查两个以上 URL 的 HTTP 错误？

How to check HTTP errors for more than two URLs?

python

http-error