我的 if, else 语句有问题
Trouble with my if, else statements
我不明白为什么我的程序会跳到最后的 "else" 语句。这是我的代码如下,也有点粗糙,因为我刚开始使用它并且我是 Java 的新手。如果还有什么需要尽管问!
我们应该编写的程序正在用于获取储物柜密码。我已经硬编码了我想要的组合,并且当我输入 12-34-56 时程序可以运行。但是,如果我输入 12-12-34 或任何其他变体,它会自动跳到程序末尾并说不匹配,即使这不应该是结果。相反,它应该打印出“猜测中的 2 个数字彼此重复。2 个数字出现在组合中。”
如果您还需要什么,请告诉我!谢谢,祝你有美好的一天! (我还使用 java 和 BlueJ 来完成所有这些工作。)
import java.util.*;
public class Combination
{
public static void main(String[] args) {
int lock1 = 12;
int lock2 = 34;
int lock3 = 56;
Scanner input = new Scanner(System.in);
System.out.print("Enter first two digits: ");
int guess1 = input.nextInt();
System.out.print("Enter second two digits: ");
int guess2 = input.nextInt();
System.out.print("Enter last two digits: ");
int guess3 = input.nextInt();
if (lock1 == guess1 && lock2 == guess2 && lock3 == guess3) {
System.out.print("Exact Match! Locker Unlocked");
}
else if (lock1 == guess1 && lock2 == guess3 && lock3 == guess2
|| lock1 == guess2 && lock2 == guess3 && lock3 == guess1
|| lock1 == guess2 && lock2 == guess1 && lock3 == guess3
|| lock1 == guess3 && lock2 == guess2 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess1 && lock3 == guess2)
{
System.out.println("All numbers match but not in the correct order");
}
else if (lock1 == guess1 && lock2 == guess1 && lock3 == guess1
|| lock1 == guess2 && lock2 == guess2 && lock3 == guess2
|| lock1 == guess3 && lock2 == guess3 && lock3 == guess3) {
System.out.println("Guess contains 3 duplicate numbers.");
System.out.println("One number in the guess appears in the combination.");
}
else if (lock1 == guess1 && lock2 == guess1 && lock3 == guess2
|| lock1 == guess1 && lock2 == guess1 && lock3 == guess3
|| lock1 == guess2 && lock2 == guess2 && lock3 == guess3
|| lock1 == guess2 && lock2 == guess2 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess3 && lock3 == guess2
|| lock1 == guess3 && lock2 == guess3 && lock3 == guess1
|| lock1 == guess2 && lock2 == guess1 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess1 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess2 && lock3 == guess2
|| lock1 == guess1 && lock2 == guess2 && lock3 == guess2
|| lock1 == guess1 && lock2 == guess3 && lock3 == guess3
|| lock1 == guess2 && lock2 == guess3 && lock3 == guess3) {
System.out.println("2 numbers in the guess are duplicates of each other." +
"2 numbers guess appear in the combination.");
}
else{
System.out.println("Sorry not a match");
}
}
}
最后两个 else-if 条件有两个问题:
lock
和 guard
需要交换。我们总是想检查所有三个猜测。目前,一个猜测被检查 twice/thrice 并且 one/two 猜测被忽略。尤其是倒数第二个else-if只有在lock1 = lock2 = lock3时才能进入。另一种发现问题的方法:要知道 Guess contains 3 duplicate numbers.
你必须检查所有三个猜测。目前,只检查一个猜测(每个案例)。
最后一个 else-if 条件缺少一些析取符。有 18 种可能的情况输入恰好两次相同的猜测,程序只检查其中的 12 种。
这里是现存和遗失的案例。每个数字代表三个猜测之一。
missing|present
-------+-------
112
113
121
122
131
133
211
212
221
223
232
233
311
313
322
323
331
332
在我将倒数第二个 else-if 条件更改为
后,程序是正确的*
guess1 == lock1 && guess2 == lock1 && guess3 == lock1
|| guess1 == lock2 && guess2 == lock2 && guess3 == lock2
|| guess1 == lock3 && guess2 == lock3 && guess3 == lock3
和最后一个 else-if 条件
guess1 == lock1 && guess2 == lock1 && guess3 == lock2
|| guess1 == lock1 && guess2 == lock1 && guess3 == lock3
|| guess1 == lock1 && guess2 == lock2 && guess3 == lock1
|| guess1 == lock1 && guess2 == lock2 && guess3 == lock2
|| guess1 == lock1 && guess2 == lock3 && guess3 == lock1
|| guess1 == lock1 && guess2 == lock3 && guess3 == lock3
|| guess1 == lock2 && guess2 == lock1 && guess3 == lock1
|| guess1 == lock2 && guess2 == lock1 && guess3 == lock2
|| guess1 == lock2 && guess2 == lock2 && guess3 == lock1
|| guess1 == lock2 && guess2 == lock2 && guess3 == lock3
|| guess1 == lock2 && guess2 == lock3 && guess3 == lock2
|| guess1 == lock2 && guess2 == lock3 && guess3 == lock3
|| guess1 == lock3 && guess2 == lock1 && guess3 == lock1
|| guess1 == lock3 && guess2 == lock1 && guess3 == lock3
|| guess1 == lock3 && guess2 == lock2 && guess3 == lock2
|| guess1 == lock3 && guess2 == lock2 && guess3 == lock3
|| guess1 == lock3 && guess2 == lock3 && guess3 == lock1
|| guess1 == lock3 && guess2 == lock3 && guess3 == lock2
* 我使用脚本检查了所有可能的组合。
提示:如果您改用数组和循环,程序会更简单、更清晰且可扩展。
我不明白为什么我的程序会跳到最后的 "else" 语句。这是我的代码如下,也有点粗糙,因为我刚开始使用它并且我是 Java 的新手。如果还有什么需要尽管问!
我们应该编写的程序正在用于获取储物柜密码。我已经硬编码了我想要的组合,并且当我输入 12-34-56 时程序可以运行。但是,如果我输入 12-12-34 或任何其他变体,它会自动跳到程序末尾并说不匹配,即使这不应该是结果。相反,它应该打印出“猜测中的 2 个数字彼此重复。2 个数字出现在组合中。”
如果您还需要什么,请告诉我!谢谢,祝你有美好的一天! (我还使用 java 和 BlueJ 来完成所有这些工作。)
import java.util.*;
public class Combination
{
public static void main(String[] args) {
int lock1 = 12;
int lock2 = 34;
int lock3 = 56;
Scanner input = new Scanner(System.in);
System.out.print("Enter first two digits: ");
int guess1 = input.nextInt();
System.out.print("Enter second two digits: ");
int guess2 = input.nextInt();
System.out.print("Enter last two digits: ");
int guess3 = input.nextInt();
if (lock1 == guess1 && lock2 == guess2 && lock3 == guess3) {
System.out.print("Exact Match! Locker Unlocked");
}
else if (lock1 == guess1 && lock2 == guess3 && lock3 == guess2
|| lock1 == guess2 && lock2 == guess3 && lock3 == guess1
|| lock1 == guess2 && lock2 == guess1 && lock3 == guess3
|| lock1 == guess3 && lock2 == guess2 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess1 && lock3 == guess2)
{
System.out.println("All numbers match but not in the correct order");
}
else if (lock1 == guess1 && lock2 == guess1 && lock3 == guess1
|| lock1 == guess2 && lock2 == guess2 && lock3 == guess2
|| lock1 == guess3 && lock2 == guess3 && lock3 == guess3) {
System.out.println("Guess contains 3 duplicate numbers.");
System.out.println("One number in the guess appears in the combination.");
}
else if (lock1 == guess1 && lock2 == guess1 && lock3 == guess2
|| lock1 == guess1 && lock2 == guess1 && lock3 == guess3
|| lock1 == guess2 && lock2 == guess2 && lock3 == guess3
|| lock1 == guess2 && lock2 == guess2 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess3 && lock3 == guess2
|| lock1 == guess3 && lock2 == guess3 && lock3 == guess1
|| lock1 == guess2 && lock2 == guess1 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess1 && lock3 == guess1
|| lock1 == guess3 && lock2 == guess2 && lock3 == guess2
|| lock1 == guess1 && lock2 == guess2 && lock3 == guess2
|| lock1 == guess1 && lock2 == guess3 && lock3 == guess3
|| lock1 == guess2 && lock2 == guess3 && lock3 == guess3) {
System.out.println("2 numbers in the guess are duplicates of each other." +
"2 numbers guess appear in the combination.");
}
else{
System.out.println("Sorry not a match");
}
}
}
最后两个 else-if 条件有两个问题:
lock
和guard
需要交换。我们总是想检查所有三个猜测。目前,一个猜测被检查 twice/thrice 并且 one/two 猜测被忽略。尤其是倒数第二个else-if只有在lock1 = lock2 = lock3时才能进入。另一种发现问题的方法:要知道Guess contains 3 duplicate numbers.
你必须检查所有三个猜测。目前,只检查一个猜测(每个案例)。最后一个 else-if 条件缺少一些析取符。有 18 种可能的情况输入恰好两次相同的猜测,程序只检查其中的 12 种。
这里是现存和遗失的案例。每个数字代表三个猜测之一。
missing|present
-------+-------
112
113
121
122
131
133
211
212
221
223
232
233
311
313
322
323
331
332
在我将倒数第二个 else-if 条件更改为
后,程序是正确的* guess1 == lock1 && guess2 == lock1 && guess3 == lock1
|| guess1 == lock2 && guess2 == lock2 && guess3 == lock2
|| guess1 == lock3 && guess2 == lock3 && guess3 == lock3
和最后一个 else-if 条件
guess1 == lock1 && guess2 == lock1 && guess3 == lock2
|| guess1 == lock1 && guess2 == lock1 && guess3 == lock3
|| guess1 == lock1 && guess2 == lock2 && guess3 == lock1
|| guess1 == lock1 && guess2 == lock2 && guess3 == lock2
|| guess1 == lock1 && guess2 == lock3 && guess3 == lock1
|| guess1 == lock1 && guess2 == lock3 && guess3 == lock3
|| guess1 == lock2 && guess2 == lock1 && guess3 == lock1
|| guess1 == lock2 && guess2 == lock1 && guess3 == lock2
|| guess1 == lock2 && guess2 == lock2 && guess3 == lock1
|| guess1 == lock2 && guess2 == lock2 && guess3 == lock3
|| guess1 == lock2 && guess2 == lock3 && guess3 == lock2
|| guess1 == lock2 && guess2 == lock3 && guess3 == lock3
|| guess1 == lock3 && guess2 == lock1 && guess3 == lock1
|| guess1 == lock3 && guess2 == lock1 && guess3 == lock3
|| guess1 == lock3 && guess2 == lock2 && guess3 == lock2
|| guess1 == lock3 && guess2 == lock2 && guess3 == lock3
|| guess1 == lock3 && guess2 == lock3 && guess3 == lock1
|| guess1 == lock3 && guess2 == lock3 && guess3 == lock2
* 我使用脚本检查了所有可能的组合。
提示:如果您改用数组和循环,程序会更简单、更清晰且可扩展。