array_diff() 函数未显示正确结果

Question

array_diff() 函数未显示正确结果：-

第一个数组：-

     Array(
    [designation_id] => 1
    [name] => Y
    [fathers_name] => Z
    [mothers_name] => F
    [spouse_name] => d
    [gender] => F
    [last_achieved_degree] => 2
    [date_of_birth] => 1960-10-17
    [date_of_joining] => 1987-02-04
)

第二个数组：-

 Array
    (
        [designation_id] => 9
        [name] => M
        [fathers_name] => N
        [mothers_name] => O
        [spouse_name] => 
        [gender] => M
        [last_achieved_degree] => 1
        [date_of_birth] => 1967-11-17
        [date_of_joining] => 2016-01-01
    )

输出：

    Array
(
    [name] => Y
    [fathers_name] => Z
    [mothers_name] => F
    [spouse_name] => d
    [gender] => F
    [last_achieved_degree] => 2
    [date_of_birth] => 1960-10-17
    [date_of_joining] => 1987-02-04
)

指定 ID 列未显示在输出结果中。如果 designation-id 值为 1，则该索引不显示在输出中，否则显示。是错误还是其他原因？

Answer 1

array_diff 计算差异而不比较键。在第二个数组中，您有 [last_achieved_degree] => 1 删除 [designation_id] => 1.
试试 array_diff_assoc.

Answer 2

由于你的数组是关联数组，所以你需要使用array_diff_assoc:-

<?php

 $a =   Array(
    'designation_id' =>1,
    'name' => 'Y',
    'fathers_name' => 'Z',
    'mothers_name' => 'F',
    'spouse_name' => 'd',
    'gender' => 'F',
    'last_achieved_degree' => 2,
    'date_of_birth' => '1960-10-17',
    'date_of_joining' => '1987-02-04'
);

$b =Array
(
    'designation_id' => 9,
    'name' => 'M',
    'fathers_name' => 'N',
    'mothers_name' => 'O',
    'spouse_name' => '',
    'gender' => 'M',
    'last_achieved_degree' => 1,
    'date_of_birth' => '1967-11-17',
    'date_of_joining' => '2016-01-01',
);

echo "<pre/>";print_r(array_diff_assoc($a,$b));

输出：- https://3v4l.org/NKbuX

查看更多描述和示例：- http://sg2.php.net/manual/en/function.array-diff-assoc.php

为什么 array_diff() 不起作用：-

array_diff() 函数未显示正确结果

array_diff() function not showing correct result

php

array-difference