过滤集合但按内部 属性 排序
Filter a collection but sort on inner property
考虑到我有如下文档的集合,我想获取如下返回的信息:
Select 来自 campaignID = 12
活动的所有条目,按 entries.questionscorrect
降序排序,限制为 10。
我已经尝试了一些查询,但我似乎陷入了这样一个事实,即我在一个级别上选择但想在较低级别上订购,即 属性.
这是我目前的情况:
db.getCollection('main').find({"id":4}, {"entries": 1}).sort({"questionscorrect": -1}).limit(2)
请问我如何用 Go (Mgo) 语法或直接 MongoDB 查询来写这个?
我不断收到返回的信息,但按
的数量排序
{
"_id": ObjectId("57f4a590a4be269aa54a0505"),
"campaignID": 12,
"name": "name-here",
"description": "description-here",
"entries": [{
"id": 1,
"nickname": "conorh",
"name": "conor h***",
"email": "ch@gmail.com",
"agreeTerms": true,
"optInMarketing": false,
"questionscnswered": 10,
"questionscorrect": 3
}, {
"id": 2,
"nickname": "bobs",
"name": "bob smyth",
"email": "bs12121@gmail.com",
"agreeTerms": true,
"optInMarketing": false,
"questionscnswered": 10,
"questionscorrect": 6
}, {
"id": 3,
"nickname": "jd12",
"name": "jane doe",
"email": "janedough@gmail.com",
"agreeTerms": true,
"optInMarketing": false,
"questionscnswered": 10,
"questionscorrect": 1
}]
}
尝试以下:
db.getCollection('main').aggregate([
{$match: {"campaignID" : 12.0}},
{$unwind:"$entries"},
{$sort: {"entries.questionscorrect": -1}},
{$group:{_id:"$_id",
"entries":{$push:"$entries"}}}
])
考虑到我有如下文档的集合,我想获取如下返回的信息:
Select 来自 campaignID = 12
活动的所有条目,按 entries.questionscorrect
降序排序,限制为 10。
我已经尝试了一些查询,但我似乎陷入了这样一个事实,即我在一个级别上选择但想在较低级别上订购,即 属性.
这是我目前的情况:
db.getCollection('main').find({"id":4}, {"entries": 1}).sort({"questionscorrect": -1}).limit(2)
请问我如何用 Go (Mgo) 语法或直接 MongoDB 查询来写这个?
我不断收到返回的信息,但按
的数量排序{
"_id": ObjectId("57f4a590a4be269aa54a0505"),
"campaignID": 12,
"name": "name-here",
"description": "description-here",
"entries": [{
"id": 1,
"nickname": "conorh",
"name": "conor h***",
"email": "ch@gmail.com",
"agreeTerms": true,
"optInMarketing": false,
"questionscnswered": 10,
"questionscorrect": 3
}, {
"id": 2,
"nickname": "bobs",
"name": "bob smyth",
"email": "bs12121@gmail.com",
"agreeTerms": true,
"optInMarketing": false,
"questionscnswered": 10,
"questionscorrect": 6
}, {
"id": 3,
"nickname": "jd12",
"name": "jane doe",
"email": "janedough@gmail.com",
"agreeTerms": true,
"optInMarketing": false,
"questionscnswered": 10,
"questionscorrect": 1
}]
}
尝试以下:
db.getCollection('main').aggregate([
{$match: {"campaignID" : 12.0}},
{$unwind:"$entries"},
{$sort: {"entries.questionscorrect": -1}},
{$group:{_id:"$_id",
"entries":{$push:"$entries"}}}
])