在 C++ 中说 "promote everything to floating before calculation" 的确定性方式

Deterministic way of saying "promote everything to floating before calculation" in C++

鉴于我更愿意在我的程序中将数字保留为 ints 或任何整数,用这些数字的浮点等价物进行任意算术运算的最方便的方法是什么?

说,我有

int a,b,c,d;
double x;

我想写

x=a/b/c/d+c/d+a;

通过将转换放在已解析的运算符树叶子中的任何地方,而不会使表达式变得一团糟,例如

x=(double)a/b/c/d+(double)c/d+a;

C 风格的宏是否可行(是否递归)?应该用新的 class 和重载的运算符来完成吗?

x=a/b/c/d+c/d+a;

这是一个相当复杂的表达式。最好给它起个名字:

double complex_expression(double a, double b, double c, double d) {
  return a/b/c/d+c/d+a;
}

现在,当您使用整数参数调用它时,由于参数的类型为 double,因此使用通常的算术转换将参数转换为 double

int a,b,c,d;
// Init them somehow
double x = complex_expression(a,b,c,d);

使用 C++11 lambda ...

int a,b,c,d;
// Init them somehow
double x = [](double a, double b, double c, double d) {
  return a/b/c/d+c/d+a; }(a,b,c,d);

... 有效,但 IMO 看起来有点笨拙。

稍微好一点?

double x = [a = (double)a, b = (double)b, c = (double)c, d = (double) d] {
    return a/b/c/d+c/d+a; }();

哦,如果你想要一些宏观的乐趣:

#define SPLICE_2(l,r) l##r
#define SPLICE_1(l,r) SPLICE_2(l,r)
#define SPLICE(l,r) SPLICE_1(l,r)

#define TREAT_AS(type, name) name = static_cast<type>(name)

#define TREAT_ALL_AS_HELPER_0(type)
#define TREAT_ALL_AS_HELPER_1(type, name)  TREAT_AS(type, name)
#define TREAT_ALL_AS_HELPER_2(type, name, ...) TREAT_AS(type, name), TREAT_ALL_AS_HELPER_1(type, __VA_ARGS__)
#define TREAT_ALL_AS_HELPER_3(type, name, ...) TREAT_AS(type, name), TREAT_ALL_AS_HELPER_2(type, __VA_ARGS__)
#define TREAT_ALL_AS_HELPER_4(type, name, ...) TREAT_AS(type, name), TREAT_ALL_AS_HELPER_3(type, __VA_ARGS__)
#define TREAT_ALL_AS_HELPER_5(type, name, ...) TREAT_AS(type, name), TREAT_ALL_AS_HELPER_4(type, __VA_ARGS__)
// expand as you will

#define TREAT_ALL_AS(type, count, ...) SPLICE(TREAT_ALL_AS_HELPER_, count)(type, __VA_ARGS__)

现在用作

double x = [TREAT_ALL_AS(double, 4, a, b, c, d)] {
  return a/b/c/d+c/d+a; }();

你也可以automatically count the number of variadic macro arguments.


但老实说,IMO 最好只编写一个命名函数。