删除部分文件名

Question

我有一堆这样的文件：

file123.txt.452
file456.txt.098
file789.txt.078

如何删除文件名中的第二个点和末尾的数字？

我尝试使用 rename，但我认为我的正则表达式不正确：

rename 's/txt.*/txt/' *

Answer 1

试试这样的正则表达式：

string.replace("(.+\.txt)(.+)", "")

Answer 2

类似于：

for f in *.txt.*; do
    g=${f%.txt.*}.txt
    mv $f $g
done

Answer 3

尝试rename 's/txt\..+/txt/' *。

\. 用于文字点，.+ 用于其后的任何内容。

命令的实际名称depends on your system。它可以是 rename、file-rename、perl-rename 或其他。上面代码使用的 rename 命令在其 man 条目中有这个：

NAME
       rename - renames multiple files

SYNOPSIS
       rename [-bfilnv] [-B prefix] [-S suffix] [-V method] [-Y prefix] [-z suffix]
       [--backup] [--basename-prefix=prefix] [--dry-run] [--force] [--help] [--no-stdin]
       [--interactive] [--just-print] [--link-only] [--prefix=prefix] [--suffix=suffix]
       [--verbose] [--version-control=method] [--version] perlexpr [files]...

DESCRIPTION
       rename renames the filenames supplied according to the rule specified as the first
       argument.  The argument is a Perl expression which is expected to modify the $_ string
       for at least some of the filenames specified.  If a given filename is not modified by
       the expression, it will not be renamed.  If no filenames are given on the command
       line, filenames will be read via standard input.

删除部分文件名

Removing part of the file names

regex

linux

bash

redhat

file-rename