想象一下如果 open() 方法抛出异常忽略然后继续下一个循环

Question

我正在尝试使用 Imagine 为超过 90k+ 相对较小的移动图像批量制作 250x250 缩略图。问题是，当我运行一个循环时，

foreach ($images as $c) {
  $imagine = new Imagine();
  $image = $imagine->open($c);
  $image->resize(new Box(250, 250))->save($outFolder);
}

有时，图像损坏，open()方法失败，抛出异常：

Unable to open image vendor/imagine/imagine/lib/Imagine/Gd/Imagine.php Line: 96

并彻底打破循环。有没有办法检查 open 是否失败？类似于：

foreach ($images as $c) {
  $imagine = new Imagine();
  $image = $imagine->open($c);
  if ($image) {
     $image->resize(new Box(250, 250))->save($outFolder);
  } else {
     echo 'corrupted: <br />';
  }
}

希望有人能提供帮助。或者，如果它不可能，你能建议一个 PHP 图像库，我可以实用地批量调整大小吗？

谢谢

Answer 1

处理异常只需使用try-catch。

来自图书馆documentation

The ImagineInterface::open() method may throw one of the following exceptions:

Imagine\Exception\InvalidArgumentException

Imagine\Exception\RuntimeException

试试这样：

$imagine = new Imagine(); // Probably no need to instantiate it in every loop
foreach ($images as $c) {
    try {
        $image = $imagine->open($c);
    } catch (\Exception $e) {
        echo 'corrupted: <br />';
        continue;
    }
    $image->resize(new Box(250, 250))->save($outFolder);
}

想象一下如果 open() 方法抛出异常忽略然后继续下一个循环

Imagine if open() method threw exception ignore then proceed to the next loop

php

image-processing

batch-file

php-imagine