替换 python 中匹配正则表达式的单词

Question

import re
replacement_patterns = [
(r'won\'t', 'will not'),
(r'can\'t', 'cannot'),
(r'i\'m', 'i am'),
(r'ain\'t', 'is not'),
(r'(\w+)\'ll', '\g<1> will'),
(r'(\w+)n\'t', '\g<1> not'),
(r'(\w+)\'ve', '\g<1> have'),
(r'(\w+)\'s', '\g<1> is'),
(r'(\w+)\'re', '\g<1> are'),
(r'(\w+)\'d', '\g<1> would')
 ]
class RegexpReplacer(object):

   def __init__(self, patterns=replacement_patterns):
      self.patterns = [(re.compile(regex), repl) for (regex, repl)          
                      in pattern]
   def replace(self, text):
      s = text
      for (pattern, repl) in self.patterns:
          (s, count) = re.subn(pattern, repl, s)
   return s


 rep=RegexpReplacer()
 print rep.replace("can't is a contradicton")

我从 Python Jacob Perkins 的《Text Processing with NLTK 2.0 Cookbook》中复制了这段代码

但是我的预期输出是：不能是矛盾

实际输出为：不能是矛盾

我无法查明 t

中的错误

Answer 1

要么使用原始字符串要么转义引号，但不能同时转义。

>>> print r'won\'t'
won\'t
>>> print 'won\'t'
won't

或者，如果您更喜欢原始字符串：

>>> print r"won't"
won't

Answer 2

您的代码存在一些缩进问题和拼写错误 - 我不太确定解释器是如何为您提供任何输出的。在我修复这些问题后，我得到了您预期的输出。

import re
replacement_patterns = [
(r'won\'t', 'will not'),
(r'can\'t', 'cannot'),
(r'i\'m', 'i am'),
(r'ain\'t', 'is not'),
(r'(\w+)\'ll', '\g<1> will'),
(r'(\w+)n\'t', '\g<1> not'),
(r'(\w+)\'ve', '\g<1> have'),
(r'(\w+)\'s', '\g<1> is'),
(r'(\w+)\'re', '\g<1> are'),
(r'(\w+)\'d', '\g<1> would')
 ]
class RegexpReplacer(object):

   def __init__(self, patterns=replacement_patterns):

      # Fixed this line - "patterns", not "pattern"
      self.patterns = [(re.compile(regex), repl) for (regex, repl) in patterns]

   def replace(self, text):
      s = text
      for (pattern, repl) in self.patterns:
          (s, count) = re.subn(pattern, repl, s)

      # Fixed indentation here
      return s


rep=RegexpReplacer()
print rep.replace("can't is a contradicton")

替换 python 中匹配正则表达式的单词

Replacing words matching regular expressions in python

python

regex

output

nltk

ontology