在 C++ 中，我的程序自动转到下一个 CIN 提示符，而不让用户添加输入

Question

这是我的代码：

#include <iostream>

using namespace std;

const int SENIOR_PRICE = 9;
const int ADULT_PRICE = 12;
const float CHILD_PRICE = 6.95;
const float TAX_RATE = .06;

int main()
{
        string name;
        string address;
        int numSeniorTickets;
        int numAdultTickets;
        int numChildTickets;

        cout << "Enter customer name:" << endl;
        cin >> name;

        cout << "Enter customer address:" << endl;
        cin >> address;

        cout << "How many senior season tickets?" << endl;
        cin >> numSeniorTickets;

        cout << "How many adult tickets?" << endl;
        cin >> numAdultTickets;

        cout << "How many child tickets?" << endl;
        cin >> numChildTickets;

        return 0;
}

用户输入姓名后，系统会提示他们输入地址。但在他们输入地址之前，它还会提示输入高级季票的数量。为什么它会跳过一行输入？这是发生了什么：

Enter customer name:
Daniel Benson
Enter customer address:
How many senior season tickets?
5
How many adult tickets?
5
How many child tickets?
5

Answer 1

cin >> name;

最多只接受输入 space。因此，如果您打印变量 name，您将得到 Daniel。如果您打印变量 address，您将得到 Benson。因此，就程序而言，它已将两个字符串作为输入。

A proof of the above statements by printing the variables after input.

您可能希望使用 cin.getline() 将 space 分隔的字符串作为输入。

在 C++ 中，我的程序自动转到下一个 CIN 提示符，而不让用户添加输入

In c++, my program automatically goes to the next CIN prompt without letting the user add input

c++

cout

cin

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